尝试根据客户在 SQL 上的购买频率查找客户数量并添加客户的销售额

Question

我正在尝试根据客户在 2019 年的购买次数来查找客户数量和销售额

txn_date Customer_ID  Transaction_Number    Sales        Reference(not in the SQL table)    
1/2/2019    1           12345                $10           First Purchase SLS
4/3/2019    1           65890                $20           Second Purchase SLS
3/22/2019   3           64453                $30           First Purchase SLS
4/3/2019    4           88567                $20           First Purchase SLS
1/23/2019   5           89464                $40           First Purchase SLS
4/3/2019    5           99674                $30           Second Purchase SLS
4/3/2019    6           32224                $20           First Purchase SLS
1/23/2019   6           46466                $30           Second Purchase SLS

我正在尝试得到以下结果：

               Customer_Count   Transaction_Count   Sum(Sales)
1st Purchase        5                 5                 $120
2nd Purchase        3                 3                 $80

我尝试了以下查询：

SELECT COUNT(DISTINCT INDIVIDUAL_ID),
CASE WHEN COUNT_OF_TRANSACTIONS = 1 THEN '1'
WHEN COUNT_OF_TRANSACTIONS = 2 THEN '2'
WHEN COUNT_OF_TRANSACTIONS = 3 THEN '3'
WHEN COUNT_OF_TRANSACTIONS = 4 THEN '4'
WHEN COUNT_OF_TRANSACTIONS  >= 5 THEN '5+' END AS TXN_TYPE,
SUM(DOLLAR_VALUE_US), 
SUM( COUNT_OF_TRANSACTIONS)

FROM customerorder

GROUP BY CASE WHEN COUNT_OF_TRANSACTIONS = 1 THEN '1'
WHEN COUNT_OF_TRANSACTIONS = 2 THEN '2'
WHEN COUNT_OF_TRANSACTIONS = 3 THEN '3'
WHEN COUNT_OF_TRANSACTIONS = 4 THEN '4'
WHEN COUNT_OF_TRANSACTIONS  >= 5 THEN '5+' END
ORDER BY 1 ASC;

我想查找客户数量及其销售额。因此，对于第一次购买，客户计数将是至少进行一次购买的任何人以及销售额。对于第二次购买，从技术上讲，它应该包括第一次购买的每个人，但只包括第二次交易的销售额。

Answer 1

如果我理解正确，您想列举每个客户的订单，然后汇总：

select seqnum, count(*) as num_customers, sum(sales)
from (select co.*,
             row_number() over (partition by customer_id order by txn_date) as seqnum
      from customerorder co
     ) co
group by seqnum
order by seqnum;