【发布时间】:2017-03-26 08:48:49
【问题描述】:
这是我的代码:
#include <LiquidCrystal.h>
#include <Stepper.h>
#include <Key.h>
#include <Keypad.h>
const int stepsPerRevolution = 200;
const byte ROWS = 4; //four rows
const byte COLS = 1; //one column
char keys[ROWS][COLS] = {
{'-'},
{'+'},
{'I'},
{'0'}};
byte rowPins[ROWS] = {6,7,8,9};
byte colPins[COLS] = {10};
int count = 0;
LiquidCrystal lcd(A5,A4,A3,A2,A1,A0);
Stepper myStepper(stepsPerRevolution, 2,4,3,5);
Keypad keypad = Keypad(makeKeymap(keys), rowPins, colPins, ROWS, COLS);
int plannedSpeed = 50;
void setup() {
lcd.begin(16,2);
Stepper.setSpeed(plannedSpeed);
Serial.begin(9600);
}
void loop() {
// put your main code here, to run repeatedly:
char key = keypad.getKey();
Serial.println(plannedSpeed);
if (key == '-') {
plannedSpeed = plannedSpeed - 1;
Serial.println(plannedSpeed);
delay(10);
}
if (key == '+') {
plannedSpeed = plannedSpeed +1;
Serial.println(plannedSpeed);
delay(10);
}
if (key == 'I') {
myStepper.step(stepsPerRevolution);
Serial.print("Running at " );
Serial.println(plannedSpeed);
delay(10);
}
}
我正在尝试对其进行编码,以便我可以使用键盘选择速度,当我按下“I”按钮时电机启动,当我按下“O”按钮时停止。我怎样才能做到这一点?谢谢!
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