来自服务器的 JSON 转换答案

【问题标题】：JSON conversion from server来自服务器的 JSON 转换
【发布时间】：2014-05-16 13:57:13
【问题描述】：

我正在开发一个使用 json 表示获取数据并使用 NSJSONSerialization 将其转换为基础对象的应用程序。

我的问题是从服务器获取数据后出现的。这是一个响应示例：

{"groups":{"15":{"idgroupcat":"15","name":"\u05e7\u05d1\u05d5\u05e6\u05d4 1","电源":{"9":{"idmaincat":"9","名称":"\u05e8\u05d0\u05e9\u05d9 1","subs":{"12":{"idsubcat":"12","idcategory":"23","name":"\u05ea\u05ea 1","title":"","workpicurl":"","numberofprofs":null,"numberofworks":null,"averageapplicationsperwork":null,"averagecloseprice":null,"averagewhen":"0"}} }}},"16":{"idgroupcat":"16","name":"组 1","mains":{"10":{"idmaincat":"10","name":"main 1","subs":{"13":{"idsubcat":"13","idcategory":"24","name":"sub 1","title":"","workpicurl":"","numberofprofs":null,"numberofworks":null,"averageapplicationsperwork":null,"averagecloseprice":null,"averagewhen":"0"}} },"11":{"idmaincat":"11","name":"main 2","subs":{"14":{"idsubcat":"14","idcategory":"25","name":"sub 2","title":"","workpicurl":"","numberofprofs":null,"numberofworks":null,"averageapplicationsperwork":null,"averagecloseprice":null,"averagewhen":"0"}} },"13":{"idmaincat":"13","name":"main 2","subs":{"16":{"idsubcat":"16","idcategory":"26","name":"sub 2","title":"","workpicurl":"","numberofprofs":null,"numberofworks":null,"averageapplicationsperwork":null,"averagecloseprice":null,"averagewhen":"0"}} },"14":{"idmaincat":"14","name":"main 2","subs":{"17":{"idsubcat":"17","idcategory":"27","name":"sub 2","title":"","workpicurl":"","numberofprofs":null,"numberofworks":null,"averageapplicationsperwork":null,"averagecloseprice":null,"averagewhen":"0"}} },"15":{"idmaincat":"15","name":"main 2","subs":{"18":{"idsubcat":"18","idcategory":"28","name":"sub 2","title":"","workpicurl":"","numberofprofs":null,"numberofworks":null,"averageapplicationsperwork":null,"averagecloseprice":null,"averagewhen":"0"}, "23":{"idsubcat":"23","idcategory":"31","name":"sub 8","title":"","workpicurl":"","numberofprofs":null,"numberofworks":null,"averageapplicationsperwork":null,"averagecloseprice":null,"averagewhen":"0"}, "24":{"idsubcat":"24","idcategory":"32","name":"sub 8","title":"","workpicurl":"","numberofprofs":null,"numberofworks":null,"averageapplicationsperwork":null,"averagecloseprice":null,"averagewhen":"0"}} }}},"17":{"idgroupcat":"17","name":"组 2","mains":{"19":{"idmaincat":"19","name":"main 4","subs":{"22":{"idsubcat":"22","idcategory":"30","name":"sub 6","title":"","workpicurl":"","numberofprofs":null,"numberofworks":null,"averageapplicationsperwork":null,"averagecloseprice":null,"averagewhen":"0"}} }}},"19":{"idgroupcat":"19","name":"组 2","mains":{"18":{"idmaincat":"18","name":"main 3","subs":{"21":{"idsubcat":"21","idcategory":"29","name":"sub 3","title":"","workpicurl":"","numberofprofs":null,"numberofworks":null,"averageapplicationsperwork":null,"averagecloseprice":null,"averagewhen":"0"}} }}},"20":{"idgroupcat":"20","name":"组 2","mains":{"20":{"idmaincat":"20","name":"main 3","subs":{"25":{"idsubcat":"25","idcategory":"33","name":"sub 3","title":"","workpicurl":"","numberofprofs":null,"numberofworks":null,"averageapplicationsperwork":null,"averagecloseprice":null,"averagewhen":"0"}} }}},"21":{"idgroupcat":"21","name":"组 2","mains":{"21":{"idmaincat":"21","name":"main 3","subs":{"26":{"idsubcat":"26","idcategory":"34","name":"sub 3","title":"","workpicurl":"","numberofprofs":null,"numberofworks":null,"averageapplicationsperwork":null,"averagecloseprice":null,"averagewhen":"0"}} }}}}}

一旦我尝试使用 NSJSONSerialization 转换它，它就会返回 null

NSDictionary *dic = [NSJSONSerialization JSONObjectWithData:data1 options:kNilOptions error:&err];

如果我使用该方法查看这是否是一个有效的 json 对象，该方法返回 NO。

我知道问题出在服务器响应中，但我不知道针对特定问题向程序员提供什么输入。服务器是用php写的

有什么建议吗？谢谢，

【问题讨论】：

错误变量err返回什么错误？
错误很重要，它是有效的JSON：jsonlint.com
"操作无法完成。(Cocoa 错误 3840.)"
这就是为什么 jsonlint 刚才对我来说很慢，所有的 SO 都在使用它。 :-) 查看导致 JSON 反序列化的几行代码也很有帮助，以证明 data1 确实是发布字符串的 NSData。
将 JSON 字符串放入数据很可能是个问题——很可能是因为使用了错误的字符串编码。需要查看更多代码。

标签： php ios objective-c json nsjsonserialization

【解决方案1】：

我认为问题在于 id 组 15，有一些未知字符（由我）未正确呈现。在调用输出方法之前尝试对服务器 php 文件进行此修复：

header ('Content-type: text/html; charset=utf-8');
echo json_encode($yourDataObject);

【讨论】：

【解决方案2】：

好的，在深入研究代码之后。

问题出现在服务器端的响应编码中。为了解决这个问题，将 utf-8 标头添加到响应中。这解决了问题，现在可以将字符串转换为基础对象。

【讨论】：

【解决方案3】：

来自 Zend Framework 1 的 Json 解码器可以与您提供的 JSON 一起工作：

    $phpNative = Zend_Json::decode($yourJSON, Zend_Json::TYPE_OBJECT);

我会复制粘贴到 $yourJSON

【讨论】：