使用 json 的 Iphone Http 请求响应

Question

我正在尝试将数据发送到服务器并获得响应。数据正在到达服务器，但我没有得到任何响应。响应数据的值为 nil bcd ，它正在抛出异常，

-JSONValue failed. Error trace is: (
"Error Domain=org.brautaset.JSON.ErrorDomain Code=11 \"Unexpected end of string\" UserInfo=0x4e2dd70 {NSLocalizedDescription=Unexpected end of string}"

谁能帮帮我....

我的代码：

NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:[NSURL URLWithString:@"http://192.168.0.83:8082/WebServiceProject/AcessWebservice?operation=login"]];
[[NSURLConnection alloc] initWithRequest:request delegate:self];

NSURLResponse *theResponse =[[NSURLResponse alloc]init];
NSError *theError = NULL;
NSArray *keys = [NSArray arrayWithObjects:@"UserId", @"Password", nil];
NSArray *objects = [NSArray arrayWithObjects:@"rajin.sasi", @"abhi1551", nil];
NSDictionary *jsonDictionary = [NSDictionary dictionaryWithObjects:objects forKeys:keys];


NSString* jsonString = [jsonDictionary JSONRepresentation];

SBJSON *jsonParser = [SBJSON new];
[jsonParser objectWithString:jsonString];

NSLog(@"Val of json parse obj is %@",jsonString);   
[request setHTTPMethod:@"POST"];

[request setValue:jsonString forHTTPHeaderField:@"json"];
responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&theResponse error:&theError];      
[request setHTTPBody:responseData];

NSMutableString* stringData= [[NSString alloc]initWithData:responseData encoding:NSUTF8StringEncoding];
NSDictionary    *jsonDictionaryResponse = [stringData JSONValue];

NSString *json_message=[jsonDictionaryResponse objectForKey:@"message"];

printf("Json string is %s **********",[json_message UTF8String]);

Answer 1

我不知道您的网络服务的详细信息，但下面的代码可能是您的问题的根源（或至少其中一个！）

[request setValue:jsonString forHTTPHeaderField:@"json"];
responseData = [NSURLConnection sendSynchronousRequest:request     returningResponse:&theResponse error:&theError];      
[request setHTTPBody:responseData];

您在设置正文之前发送请求，我认为应该包括您的jsonString 内容。另外，您将jsonString 分配给标题字段，您确定这是您想要的吗？以下是对可能可行的猜测：

[request setValue:@"application/json" forHTTPHeaderField:@"Content-type"];
[request setHTTPBody:jsonString];
responseData = // rest of your code here....

我建议您仔细查看该代码，因为它目前一团糟！你有两个NSURLConnection 请求，一个asynchronous 和一个synchronous，很难理解你在做什么/为什么要做这一切，所以查看Apple 的文档以获取NSURLConnection 并整理你的代码。 .

[编辑]

这是我给你的建议：

NSError *theError = nil;
NSArray *keys = [NSArray arrayWithObjects:@"UserId", @"Password", nil];
NSArray *objects = [NSArray arrayWithObjects:@"rajin.sasi", @"abhi1551", nil];
NSDictionary *jsonDictionary = [NSDictionary dictionaryWithObjects:objects forKeys:keys];
NSString *jsonString = [jsonDictionary JSONRepresentation];
NSData *jsonData = [jsonString dataUsingEncoding:NSUTF8StringEncoding];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:[NSURL URLWithString:@"http://192.168.0.83:8082/WebServiceProject/AcessWebservice?operation=login"]];
[request setValue:jsonString forHTTPHeaderField:@"json"];
[request setHTTPMethod:@"POST"];
[request setHTTPBody:jsonData];
NSURLResponse *theResponse =[[NSURLResponse alloc]init];
NSData *data = [NSURLConnection sendSynchronousRequest:request returningResponse:&theResponse error:&theError];      
NSMutableString *string = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
NSDictionary *jsonDictionaryResponse = [string JSONValue];
[string release];
[theResponse release];

Answer 2

    NSData* responseData = nil;

    NSURL *url=[NSURL URLWithString:[URLString stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]];

    responseData = [NSMutableData data] ;

    NSMutableURLRequest *request=[NSMutableURLRequest requestWithURL:url];
    [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];


    NSString *bodydata=[NSString stringWithFormat:@"%@",jsonString];

    NSData *req=[NSData dataWithBytes:[bodydata UTF8String] length:[bodydata length]];

    [request setHTTPMethod:@"POST"];
    [request setHTTPBody:req];
    [request setTimeoutInterval:15.0];

    NSURLResponse* response;
    NSError* error = nil;

    responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];

    NSError *dataError;

    NSMutableDictionary * jsonDict = [[NSMutableDictionary alloc]init];

    if (responseData != nil)
    {
        jsonDict = [NSJSONSerialization JSONObjectWithData:responseData
                                                   options:kNilOptions
                                                     error:&dataError];
           NSLog(@"jsonDict:%@",jsonDict);

    }

Answer 3

试试这个：

[request setValue:jsonString forHTTPHeaderField:@"json"];
responseData = [NSURLConnection sendSynchronousRequest:request     returningResponse:&theResponse error:&theError];      
[request setHTTPBody:responseData];