【问题标题】:Json error when making post request to server向服务器发出发布请求时出现 Json 错误
【发布时间】:2025-12-14 00:15:02
【问题描述】:

经过数小时搜索堆栈并查看类似问题后,我仍然无法使其正常工作。请帮助指导我!

我要做的就是向我的服务器提交一个用户名并将其保存在 MySQL 中 - 只是为了让它工作......

我可以将用户名发送到服务器,甚至可以将硬编码的数据返回给 iOS 模拟器以设置标签的文本,但是一旦我添加了将数据保存到 MySQL 的函数,我就会收到错误: "Error Domain=NSCocoaErrorDomain Code=3840 "字符 0 周围的值无效。" UserInfo={NSDebugDescription=字符 0 周围的值无效。}"

对不起,奇怪的命名约定,我偏离了我所遵循的教程。谢谢!

SWIFT 3:

func Apitest(name: String) {

    let json = ["user" : name]

    do {
        let jsonData = try JSONSerialization.data(withJSONObject: json, options: .prettyPrinted)

        let url = NSURL(string: "I put the actual path here, don't worry")!
        let request = NSMutableURLRequest(url: url as URL)
        request.httpMethod = "POST"

        request.setValue("application/json; charset=utf-8", forHTTPHeaderField: "Content-Type")
        request.httpBody = jsonData

        let task = URLSession.shared.dataTask(with: request as URLRequest){ data, response, error in
            if error != nil{
                print("First Error -> \(error)")
                return
            }
            do {
                let result = try JSONSerialization.jsonObject(with: data!, options: .allowFragments) as? [String:AnyObject]
                print("Result -> \(result!)")

                let label = result?["messages"] as! String

                print(label)

                self.setupLabel(text: label)

            } catch {
                print("Second Error -> \(error)")
            }
        }

        task.resume()
    } catch {
        print(error)
    }
}

API 代码(python/flask)

@app.route('/api/get_messages/') methods=['POST'])
def get_messages():
json = request.get_json()

api_test(json['user'])

return jsonify({'messages':json['user']})

MySQL函数:

def api_test(user):
c, conn = connection()
c.execute("INSERT INTO users (email) VALUES (%s)", (user))
conn.commit()
conn.close()
c.close()

【问题讨论】:

    标签: python ios json flask swift3


    【解决方案1】:

    通过查看您的代码,我会说您的插入命令应该是:

    c.execute("INSERT INTO users (email) VALUES (%s)", (user))
    

    【讨论】:

    • 抱歉,原来是这样。我没有粘贴那行,是我输入的。