【发布时间】:2025-12-14 00:15:02
【问题描述】:
经过数小时搜索堆栈并查看类似问题后,我仍然无法使其正常工作。请帮助指导我!
我要做的就是向我的服务器提交一个用户名并将其保存在 MySQL 中 - 只是为了让它工作......
我可以将用户名发送到服务器,甚至可以将硬编码的数据返回给 iOS 模拟器以设置标签的文本,但是一旦我添加了将数据保存到 MySQL 的函数,我就会收到错误: "Error Domain=NSCocoaErrorDomain Code=3840 "字符 0 周围的值无效。" UserInfo={NSDebugDescription=字符 0 周围的值无效。}"
对不起,奇怪的命名约定,我偏离了我所遵循的教程。谢谢!
SWIFT 3:
func Apitest(name: String) {
let json = ["user" : name]
do {
let jsonData = try JSONSerialization.data(withJSONObject: json, options: .prettyPrinted)
let url = NSURL(string: "I put the actual path here, don't worry")!
let request = NSMutableURLRequest(url: url as URL)
request.httpMethod = "POST"
request.setValue("application/json; charset=utf-8", forHTTPHeaderField: "Content-Type")
request.httpBody = jsonData
let task = URLSession.shared.dataTask(with: request as URLRequest){ data, response, error in
if error != nil{
print("First Error -> \(error)")
return
}
do {
let result = try JSONSerialization.jsonObject(with: data!, options: .allowFragments) as? [String:AnyObject]
print("Result -> \(result!)")
let label = result?["messages"] as! String
print(label)
self.setupLabel(text: label)
} catch {
print("Second Error -> \(error)")
}
}
task.resume()
} catch {
print(error)
}
}
API 代码(python/flask)
@app.route('/api/get_messages/') methods=['POST'])
def get_messages():
json = request.get_json()
api_test(json['user'])
return jsonify({'messages':json['user']})
MySQL函数:
def api_test(user):
c, conn = connection()
c.execute("INSERT INTO users (email) VALUES (%s)", (user))
conn.commit()
conn.close()
c.close()
【问题讨论】:
标签: python ios json flask swift3