从 Parse 中检索数组并将它们保存在具有相应值的字典中。 [字符串（）：[字符串]（）]

Question

我是这里的初学者，我在从解析中检索数组时遇到问题.. 我的问题如下..

我创建了一个名为“TypeOfNumbers”的类

var typeOfNumbers:PFObject = PFObject(className: "TypeOfNumbers")
    typeOfNumbers["type"] = "Prime"
    typeOfNumbers["numbers"] = ["2", "3", "5", "7", "11", "13"]
    typeOfNumbers.saveInBackground()

现在假设我们在“TypeOfNumbers”类中有另一行，如下所示：

var typeOfNumbers:PFObject = PFObject(className: "TypeOfNumbers")
    typeOfNumbers["type"] = "Squares
    typeOfNumbers["numbers"] = ["1", "4", "9", "16", "25"]
    typeOfNumbers.saveInBackground()

现在我也想检索这两个数组及其对应的类型。

假设我想检索这些数组并希望保存在字典中，例如：

[素数：[“2”，“3”，“5”，“7”，“11”，“13”]，正方形：[“2”，“3”，“5”，“7” , "11", "13"]]

Answer 1

您可以尝试编写以下代码：

var dictionary = [String:String]
var number = 0
let typeOfNumbersAsArrayOfStrings = typeOfNumbers["numbers"] as! [String]
let typeOfNumbersAsArrayOfStrings2 = typeOfNumbers["numbers"] as! [String]
for object in typeOfNumbersAsArrayOfStrings {
     dictionary["\(object)"] = typeOfNumbersAsArrayOfStrings2[number]
     ++number
}