UINavigationController 回退不止一步答案

【问题标题】：UINavigationController back to more than one stepUINavigationController 回退不止一步
【发布时间】：2012-06-19 13:11:06
【问题描述】：

是否可以在 UINavigationController 中弹出多个视图控制器？假设我想退后两步。

【问题讨论】：

标签： ios cocoa-touch uinavigationcontroller

【解决方案1】：

是的，你可以通过做类似的事情来实现这一点

//Your navigation controller
UINavigationController *nav;

//Get the view controller that is 2 step behind
UIViewController *controller = [nav.viewControllers objectAtIndex:nav.viewControllers.count - 2];

//Go to that controller
[nav popToViewController:controller animated:YES];

【讨论】：

【解决方案2】：

斯威夫特

Omar 提出的相同解决方案是：

// Get the previous Controller.
let targetController: UIViewController = navigationController!.viewControllers[navigationController!.viewControllers.count - 2]

// And go to that Controller
navigationController?.popToViewController(targetController, animated: true)

在我的情况下，我需要支持 2 个控制器，因此，我必须采用堆栈中的第 3 个支持。我真正的解决方案是：

// obtaining origin controller
let controller: UIViewController = navigationController!.viewControllers[navigationController!.viewControllers.count - 2]

// If was the expected controller (An enroll action)
if controller is CreateChatViewController {

    // I get the previous controller from it, in this case, the 3rd back in stack
    let newControllerTarget = navigationController!.viewControllers[navigationController!.viewControllers.count - 3]

    // And finally sends back to desired controller
    navigationController?.popToViewController(newControllerTarget, animated: true)
}

【讨论】：