我想摆脱 NSAttributedString 前面和末尾的空白（修剪它）。我不能简单地将其转换为字符串并进行修剪，因为其中有图像（附件）。 我该怎么做？
【问题讨论】：
标签： ios swift cocoa-touch
如下创建NSAttributedString 的扩展名。
extension NSAttributedString {
public func attributedStringByTrimmingCharacterSet(charSet: CharacterSet) -> NSAttributedString {
let modifiedString = NSMutableAttributedString(attributedString: self)
modifiedString.trimCharactersInSet(charSet: charSet)
return NSAttributedString(attributedString: modifiedString)
}
}
extension NSMutableAttributedString {
public func trimCharactersInSet(charSet: CharacterSet) {
var range = (string as NSString).rangeOfCharacter(from: charSet as CharacterSet)
// Trim leading characters from character set.
while range.length != 0 && range.location == 0 {
replaceCharacters(in: range, with: "")
range = (string as NSString).rangeOfCharacter(from: charSet)
}
// Trim trailing characters from character set.
range = (string as NSString).rangeOfCharacter(from: charSet, options: .backwards)
while range.length != 0 && NSMaxRange(range) == length {
replaceCharacters(in: range, with: "")
range = (string as NSString).rangeOfCharacter(from: charSet, options: .backwards)
}
}
}
并在要使用的 viewController 中使用。像这样
let attstring = NSAttributedString(string: "this is test message. Please wait. ")
let result = attstring.attributedStringByTrimmingCharacterSet(NSCharacterSet.whitespaceAndNewlineCharacterSet())
【讨论】：
即使在文本中使用表情符号也可以使用
extension NSAttributedString {
/** Will Trim space and new line from start and end of the text */
public func trimWhiteSpace() -> NSAttributedString {
let invertedSet = CharacterSet.whitespacesAndNewlines.inverted
let startRange = string.utf16.description.rangeOfCharacter(from: invertedSet)
let endRange = string.utf16.description.rangeOfCharacter(from: invertedSet, options: .backwards)
guard let startLocation = startRange?.upperBound, let endLocation = endRange?.lowerBound else {
return NSAttributedString(string: string)
}
let location = string.utf16.distance(from: string.startIndex, to: startLocation) - 1
let length = string.utf16.distance(from: startLocation, to: endLocation) + 2
let range = NSRange(location: location, length: length)
return attributedSubstring(from: range)
}
}
用法
let attributeString = NSAttributedString(string: "\n\n\n Hi ? ??????????????????????????????????????? buddy. ")
let result = attributeString.trimWhiteSpace().string // Hi ? ??????????????????????????????????????? buddy.
【讨论】：
Swift 4 及以上版本
extension NSMutableAttributedString {
func trimmedAttributedString() -> NSAttributedString {
let invertedSet = CharacterSet.whitespacesAndNewlines.inverted
let startRange = string.rangeOfCharacter(from: invertedSet)
let endRange = string.rangeOfCharacter(from: invertedSet, options: .backwards)
guard let startLocation = startRange?.upperBound, let endLocation = endRange?.lowerBound else {
return NSAttributedString(string: string)
}
let location = string.distance(from: string.startIndex, to: startLocation) - 1
let length = string.distance(from: startLocation, to: endLocation) + 2
let range = NSRange(location: location, length: length)
return attributedSubstring(from: range)
}
}
使用：
let string = "This is string with some space in the end. "
let attributedText = NSMutableAttributedString(string: string).trimmedAttributedString()
【讨论】：
我做了一个 swift 3 实现，以防万一有人感兴趣：
/**
Trim an attributed string. Can for example be used to remove all leading and trailing spaces and line breaks.
*/
public func attributedStringByTrimmingCharactersInSet(set: CharacterSet) -> NSAttributedString {
let invertedSet = set.inverted
let rangeFromStart = string.rangeOfCharacter(from: invertedSet)
let rangeFromEnd = string.rangeOfCharacter(from: invertedSet, options: .backwards)
if let startLocation = rangeFromStart?.upperBound, let endLocation = rangeFromEnd?.lowerBound {
let location = string.distance(from: string.startIndex, to: startLocation) - 1
let length = string.distance(from: startLocation, to: endLocation) + 2
let newRange = NSRange(location: location, length: length)
return self.attributedSubstring(from: newRange)
} else {
return NSAttributedString()
}
}
【讨论】：
事实证明，Unicode 字符串很难哈哈哈！此处发布的其他解决方案是一个很好的起点，但在使用非拉丁字符串时它们对我来说崩溃了。
每当在 Swift 字符串中使用索引或范围时，我们需要使用 String.Index 而不是普通的 Int。从Range<String.Index> 创建NSRange 必须使用NSRange(swiftRange, in: String)。
话虽如此，此代码建立在其他答案的基础上，但使其具有 unicode-proof：
public extension NSMutableAttributedString {
/// Trims new lines and whitespaces off the beginning and the end of attributed strings
func trimmedAttributedString() -> NSAttributedString {
let invertedSet = CharacterSet.whitespacesAndNewlines.inverted
let startRange = string.rangeOfCharacter(from: invertedSet)
let endRange = string.rangeOfCharacter(from: invertedSet, options: .backwards)
guard let startLocation = startRange?.lowerBound, let endLocation = endRange?.lowerBound else {
return NSAttributedString(string: string)
}
let trimmedRange = startLocation...endLocation
return attributedSubstring(from: NSRange(trimmedRange, in: string))
}
}
【讨论】：
Swift 3.2 版本：
extension NSAttributedString {
public func trimmingCharacters(in characterSet: CharacterSet) -> NSAttributedString {
let modifiedString = NSMutableAttributedString(attributedString: self)
modifiedString.trimCharacters(in: characterSet)
return NSAttributedString(attributedString: modifiedString)
}
}
extension NSMutableAttributedString {
public func trimCharacters(in characterSet: CharacterSet) {
var range = (string as NSString).rangeOfCharacter(from: characterSet)
// Trim leading characters from character set.
while range.length != 0 && range.location == 0 {
replaceCharacters(in: range, with: "")
range = (string as NSString).rangeOfCharacter(from: characterSet)
}
// Trim trailing characters from character set.
range = (string as NSString).rangeOfCharacter(from: characterSet, options: .backwards)
while range.length != 0 && NSMaxRange(range) == length {
replaceCharacters(in: range, with: "")
range = (string as NSString).rangeOfCharacter(from: characterSet, options: .backwards)
}
}
}
【讨论】：
以下代码将满足您的要求。
var attString: NSAttributedString = NSAttributedString(string: " this is att string")
let trimmedString = attString.string.stringByTrimmingCharactersInSet(NSCharacterSet.whitespaceCharacterSet())
【讨论】：
String 而不是NSAttributedString。您只需将String 转换为NSAttributedString 即可。漂亮的两行代码。