【发布时间】：2016-01-19 02:31:12
【问题描述】：
所以当我运行我的代码时，它会在 awakeFromNib 函数中不断出错。它似乎无法识别我从 IBOutlet 定义的 UIScrollView。这是我的 UITableViewCell 代码：
import UIKit
class ItemDetailsCell: UITableViewCell, UIScrollViewDelegate {
@IBOutlet weak var centerImage: UIImageView!
@IBOutlet weak var labelBlack: UILabel!
@IBOutlet weak var heading: UILabel!
@IBOutlet weak var body: UILabel!
@IBOutlet weak var tableScrollView: UIScrollView!
var pageImages: [UIImage] = []
var pageViews: [UIImageView?] = []
static var parentView : ItemDetailsVC!;
override func awakeFromNib() {
super.awakeFromNib()
//tableScrollView.delegate = self;
var scrollViewWidth = ItemDetailsCell.parentView.scrollViewWidth
var scrollViewHeight = ItemDetailsCell.parentView.scrollViewHeight
if let tableCheck = ItemDetailsCell.parentView.scrollImages as [Dictionary<Int,UIImage>]? {
if ItemDetailsCell.parentView.scrollImages.count > 0 {
for var subviewCounter: Int = 0; subviewCounter <= tableCheck.count; subviewCounter++ {
for scrollImage in tableCheck {
if let imgToInsert = scrollImage[subviewCounter] as UIImage? {
let viewWidth = CGFloat(subviewCounter-1)
let imgTwo = UIImageView(frame: CGRectMake(scrollViewWidth * viewWidth, 0, scrollViewWidth, scrollViewHeight))
imgTwo.image = imgToInsert
imgTwo.contentMode = .ScaleAspectFit
imgTwo.userInteractionEnabled = true
var gesture = UITapGestureRecognizer(target: self, action: "tappedOnImage:")
var pinchGesture = UIPinchGestureRecognizer(target: self, action: "pinchedImage:")
imgTwo.addGestureRecognizer(gesture)
imgTwo.addGestureRecognizer(pinchGesture)
tableScrollView.addSubview(imgTwo)
} else {
println("no match")
}
}
}
所以我在另一个 ViewController 中有一个 UITableView，它有 2 个原型单元格，一个带有 UIScrollView，另一个带有文本标签。这是我的 UITableView 代码：
func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
if indexPath.row == 0 {
let myCell = tableView.dequeueReusableCellWithIdentifier("Cell", forIndexPath: indexPath) as! ItemDetailsCell
myCell.centerImage.image = mainImage
myCell.heading.text = detailsHeadings[indexPath.row]
let headingString = detailsHeadings[indexPath.row]
myCell.body.text = details[headingString]
println("Label Height")
println(myCell.labelBlack.frame.height)
myCell.tableScrollView.frame = scrollViewOrigFrame
return myCell
} else {
我得到的错误是当它加载时我得到一个错误，即“致命错误：在 tableScrollView 变量上展开可选值时意外发现 nil”。
知道为什么我会得到这个吗？我可能没有采取最好的方式在表格内进行滚动图像查看器，但我找不到太多相关信息。
【问题讨论】：
标签： ios swift uitableview uiscrollview