TypeError：无法读取未定义的属性“文件”答案

【问题标题】：TypeError: Cannot read property 'File' of undefinedTypeError：无法读取未定义的属性“文件”
【发布时间】：2018-06-03 19:10:57
【问题描述】：

我想将文件上传到我的 firebase 存储并将 url 存储在数据库中。我遵循了我在此link 上找到的示例。我有两个不同的 ts 课程。当我点击提交按钮时，我的pushFileToStorage 函数出现了一个错误，上面写着TypeError: Cannot read property 'file' of undefined。谁能帮我解决这个问题？。

//these are from two different class files
//fileUpload.ts
export class FileUpload {
  name: string;
  Url: string;
  File: File;

  constructor(prdFile: File) {
    this.prdFile = prdFile;
  }
}

//product.ts
export class Product {
  $prdKey: string;
  prdName: string;
  prdImage: string;
  prdDescription: string;
}

//product.service.ts

basePath = '/Product';
pushFileToStorage(fileUpload: FileUpload, Product: Product, progress: {
  percentage: number
}) {
  const storageRef = firebase.storage().ref();
  const uploadTask = storageRef.child(`${this.basePath}/${fileUpload.File.name}`).put(fileUpload.File);

  uploadTask.on(firebase.storage.TaskEvent.STATE_CHANGED,
    (snapshot) => {
      // in progress
      const snap = snapshot as firebase.storage.UploadTaskSnapshot
      progress.percentage = Math.round((snap.bytesTransferred / snap.totalBytes) * 100)
    },
    (error) => {
      // fail
      console.log(error)
    },
    () => {
      // success
      this.productList.push({
        prdName: Product.prdName,
        prdImage: Product.prdImage = fileUpload.Url = uploadTask.snapshot.downloadURL,
        prdDescription: Product.prdDescription,
      })
      this.saveFileData(fileUpload)
    }
  );
}

private saveFileData(fileUpload: FileUpload) {
  this.firebase.list(`${this.basePath}/`).push(fileUpload);
}

//product.component.ts
currentFileUpload: FileUpload;
onSubmit(form: NgForm) {

  this.ProductService.pushFileToStorage(this.currentFileUpload, this.ProductService.selectedProduct, this.progress);
}

【问题讨论】：

你在product.component.ts文件中的哪里设置this.currentFileUpload属性？
喜欢这个currentFileUpload: FileUpload;CMIIW

标签： html angular typescript firebase firebase-storage

【解决方案1】：

当您执行currentFileUpload: FileUpload; 时，您并没有为它提供任何值，您只是提供currentFileUpload 的类型。该值仍为undefined。将其初始化为实例：

currentFileUpload: FileUpload = fileUploadInstance; // Get the instance somehow

【讨论】：