【发布时间】：2021-08-05 13:59:28
【问题描述】：
我正在使用 Cloud Firestore 做我的第一个 IOS 应用程序，并且必须重复对我的数据库进行相同的查询。我想摆脱重复的代码行。这是文档 ID 重复的 func 示例。我还使用其他查询作为.delete()、.addSnapshotListener()、.setData()。我应该以某种方式重构所有这些查询，还是因为它们只用过一次就留下它们？
@objc func updateUI() {
inputTranslate.text = ""
inputTranslate.backgroundColor = UIColor.clear
let user = Auth.auth().currentUser?.email
let docRef = db.collection(K.FStore.collectionName).document(user!)
docRef.getDocument { [self] (document, error) in
if let document = document, document.exists {
let document = document
let label = document.data()?.keys.randomElement()!
self.someNewWord.text = label
// Fit the label into screen
self.someNewWord.adjustsFontSizeToFitWidth = true
self.checkButton.isHidden = false
self.inputTranslate.isHidden = false
self.deleteBtn.isHidden = false
} else {
self.checkButton.isHidden = true
self.inputTranslate.isHidden = true
self.deleteBtn.isHidden = true
self.someNewWord.adjustsFontSizeToFitWidth = true
self.someNewWord.text = "Add your first word to translate"
updateUI()
}
}
}
@IBAction func checkButton(_ sender: UIButton) {
let user = Auth.auth().currentUser?.email
let docRef = db.collection(K.FStore.collectionName).document(user!)
docRef.getDocument { (document, error) in
let document = document
let label = self.someNewWord.text!
let currentTranslate = document!.get(label) as? String
let translateField = self.inputTranslate.text!.lowercased().trimmingCharacters(in: .whitespaces)
if translateField == currentTranslate {
self.inputTranslate.backgroundColor = UIColor.green
DispatchQueue.main.asyncAfter(deadline: .now() + 0.2) { [self] in
self.inputTranslate.backgroundColor = UIColor.clear
updateUI()}
} else {
self.inputTranslate.backgroundColor = UIColor.red
self.inputTranslate.shakingAndRedBg()
DispatchQueue.main.asyncAfter(deadline: .now() + 0.2) { [self] in
self.inputTranslate.backgroundColor = UIColor.clear
self.inputTranslate.text = ""
}
}
}
}
func deletCurrentWord () {
let user = Auth.auth().currentUser?.email
let docRef = db.collection(K.FStore.collectionName).document(user!)
docRef.getDocument { (document, err) in
let document = document
if let err = err {
print("Error getting documents: \(err)")
} else {
let array = document!.data()
let counter = array!.count
if counter == 1 {
// The whole document will deleted together with a last word in list.
let user = Auth.auth().currentUser?.email
self.db.collection(K.FStore.collectionName).document(user!).delete() { err in
if let err = err {
print("Error removing document: \(err)")
} else {
self.updateUI()
}
}
} else {
// A current word will be deleted
let user = Auth.auth().currentUser?.email
let wordForDelete = self.someNewWord.text!
self.db.collection(K.FStore.collectionName).document(user!).updateData([
wordForDelete: FieldValue.delete()
]) { err in
if let err = err {
print("Error updating document: \(err)")
} else {
self.updateUI()
}
}
}
}
}
}
另一个查询示例
func loadMessages() {
let user = Auth.auth().currentUser?.email
let docRef = db.collection(K.FStore.collectionName).document(user!)
docRef.addSnapshotListener { (querySnapshot, error) in
self.messages = []
if let e = error {
print(e)
} else {
if let snapshotDocuments = querySnapshot?.data(){
for item in snapshotDocuments {
if let key = item.key as? String, let translate = item.value as? String {
let newMessage = Message(key: key, value: translate)
self.messages.append(newMessage)
}
}
DispatchQueue.main.async {
self.messages.sort(by: {$0.value > $1.value})
self.secondTableView.reloadData()
let indexPath = IndexPath(row: self.messages.count - 1, section: 0)
self.secondTableView.scrollToRow(at: indexPath, at: .top, animated: false)
}
}
}
}
}
}
【问题讨论】：
标签： ios swift firebase duplicates