【发布时间】:2014-10-03 11:29:58
【问题描述】:
所以我有这个客户不愿意支付像 PushWoosh 这样的第三方服务来处理推送通知,我需要使用这个插件来实现它们:https://github.com/phonegap-build/PushPlugin on Phonegap Build
这是我目前所拥有的:
应该发送通知的 PHP 文件(在部分教程中找到)
<?php
// Set parameters:
$apnsHost = 'gateway.sandbox.push.apple.com';
$apnsPort = 2195;
$apnsCert = 'apns-dev.pem';
// Setup stream:
$streamContext = stream_context_create();
stream_context_set_option($streamContext, 'ssl', 'local_cert', $apnsCert);
// Open connection:
$apns = stream_socket_client(
'ssl://' . $apnsHost . ':' . $apnsPort,
$error,
$errorString,
2,
STREAM_CLIENT_CONNECT,
$streamContext
);
// Get the device token (fetch from a database for example):
$deviceToken = '...';
// Create the payload:
$message = 'Hallo iOS';
// If message is too long, truncate it to stay within the max payload of 256 bytes.
if (strlen($message) > 125) {
$message = substr($message, 0, 125) . '...';
}
$payload['aps'] = array('alert' => $message, 'badge' => 1, 'sound' => 'default');
$payload = json_encode($payload);
// Send the message:
$apnsMessage
= chr(0) . chr(0) . chr(32) . pack('H*', str_replace(' ', '', $deviceToken)) . chr(0) . chr(strlen($payload))
. $payload;
// fwrite($apns, $apnsMessage);
// Close connection:
@socket_close($apns);
fclose($apns);
?>
我应该在应用程序中添加的 JS 代码(我认为)也在该部分教程中找到:
// Setup push notifications:
try
{
var pushNotification = window.plugins.pushNotification;
if (window.device.platform == 'iOS') {
// Register for IOS:
pushNotification.register(
pushSuccessHandler,
pushErrorHandler, {
"badge":"true",
"sound":"true",
"alert":"true",
"ecb":"onNotificationAPNS"
}
);
}
}
catch(err)
{
// For this example, we'll fail silently ...
console.log(err);
}
/**
* Success handler for when connected to push server
* @param result
*/
var pushSuccessHandler = function(result)
{
console.log(result);
};
/**
* Error handler for when not connected to push server
* @param error
*/
var pushErrorHandler = function(error)
{
console.log(error);
};
/**
* Notification from Apple APNS
* @param e
*/
var onNotificationAPNS = function(e)
{
// ...
};
还有一个应该在我将创建的数据库中插入设备令牌的文件。我应该将此文件称为:../deviceAdd.php?token=XXXXXXX
问题是我不知道如何将该设备令牌传递给 deviceAdd 文件。
非常感谢任何帮助!
【问题讨论】:
标签: php jquery push-notification apple-push-notifications phonegap-build