.htaccess 规则从 url 跳过 $2 不匹配的 uri 段

Question

我想要下面的请求和响应

• 1
  请求：https://example.com/de/
  预期：https://example.com/de

• 2
  请求：https://example.com/de/fr/path
  预期：https://example.com/de/path

• 3 #默认英文
  https://example.com/def/frq/path
  https://example.com/en

RewriteEngine On

#Check for files that do not contain the language string
RewriteCond %{REQUEST_URI} !^/[a-z]{2}/.*
RewriteRule ^(.*)$ https://%{HTTP_HOST}/en [R=301,L]

#Capture the language string and present it as the variable
RewriteCond %{REQUEST_URI} ^/([a-z]{2})/
RewriteRule ^([a-z]{2})/(.*)$ https://%{HTTP_HOST}/%1/%2 [R=301,L]

尝试对 %2 段 uri 进行一些更改，但到目前为止没有任何帮助，之前有人这样做过吗？ 如果需要更多描述，请告诉我

Answer 1

使用您显示的示例/尝试，请尝试以下操作。请确保在测试您的 URL 之前清除您的浏览器缓存。

将这些规则保留在 .htaccess 规则文件的顶部。我假设您有规则可以在您的 htaccess 规则文件中提供新重写的 url。

RewriteEngine ON
##1st kind of urls, to remove / from end of it.
RewriteRule ^([a-zA-Z]{2})/?$ $1 [R=301,L]

##Handle https://example.com/de/fr/en/de/en TO https://example.com/de urls.
RewriteRule ^([a-zA-Z]{2})/(?:[a-zA-Z]{2}/)*(?:[a-zA-Z]{2})/?$ $1 [R=301,L]

##Handle https://example.com/de/fr/path TO https://example.com/de/path urls.
RewriteRule ^([a-zA-Z]{2})/(?:[a-zA-Z]{2}/)*(.*)/?$ $1/$2 [R=301,L]

##handle https://example.com/def/frq/path TO https://example.com/en urls here.
RewriteRule ^([a-zA-Z]{3,})/.*$ en [R=301,L]

Online demo for 3rd rule regex

Online demo for 2nd rule regex

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编辑： 或者检查以 2 个字母特定语言开头的规则，然后尝试以下，我使用了 en、us、de、fr 语言，您可以添加也可以根据您的需要进行更多操作。

RewriteEngine ON
##1st kind of urls, to remove / from end of it.
RewriteRule ^(en|us|de|fr)/?$ $1 [NC,R=301,L]

##Handle https://example.com/de/fr/en/de/en TO https://example.com/de urls.
RewriteRule ^(en|us|de|fr)/(?:(?:en|us|de|fr)/)*(?:en|us|de|fr)/?$ $1 [NC,R=301,L]

##Handle https://example.com/de/fr/path TO https://example.com/de/path urls.
RewriteRule ^(en|us|de|fr)/(?:(?:en|us|de|fr)/)*(.*)/?$ $1/$2 [NC,R=301,L]

##handle https://example.com/def/frq/path TO https://example.com/en urls here.
RewriteRule ^([a-zA-Z]{3,})/.*$ en [R=301,L]