如何在不使用 python 保留目录的情况下提取文件夹中的所有 .zip 扩展名？

Question

这是我的代码，我不知道如何循环文件夹中的每个 .zip，请帮助我：我希望将 5 个 zip 文件的所有内容提取到一个文件夹中，不包括其目录名

import os
import shutil
import zipfile
my_dir = r"C:\\Users\\Guest\\Desktop\\OJT\\scanner\\samples_raw"

my_zip = r"C:\\Users\\Guest\\Desktop\\OJT\\samples\\001-100.zip"
with zipfile.ZipFile(my_zip) as zip_file:
zip_file.setpassword(b"virus")
for member in zip_file.namelist():
    filename = os.path.basename(member)
    # skip directories
    if not filename:
        continue

    # copy file (taken from zipfile's extract)
    source = zip_file.open(member)
    target = file(os.path.join(my_dir, filename), "wb")
    with source, target:
        shutil.copyfileobj(source, target)

Answer 1

重复问题，请参考以下链接。

How to extract zip file recursively in Pythonn

Answer 2

您正在寻找的是glob。可以这样使用：

#<snip>
import glob

#assuming all your zip files are in the directory below.
for my_zip in glob.glob(r"C:\\Users\\Guest\\Desktop\\OJT\\samples\\*.zip"):
    with zipfile.ZipFile(my_zip) as zip_file:
        zip_file.setpassword(b"virus")
        for member in zip_file.namelist():
            #<snip> rest of your code here.