【发布时间】:2021-02-19 17:41:48
【问题描述】:
我正在尝试比较两个数据框中的经纬度坐标。如果 latitude_fuze 的差异
这是我正在测试的代码。
lat1 = df_result['latitude_fuze']
lon1 = df_result['longitude_fuze']
lat2 = df_airports['latitude_air']
lon2 = df_airports['longitude_air']
fuze_rows=range(df_result.shape[0])
air_rows=range(df_airports.shape[0])
for r in fuze_rows:
lat = df_result.loc[r,lat1]
max_lat = lat + .01
min_lat = lat - .01
lon = df_result.loc[r,lon1]
max_lon = lon + .01
min_lon = lon - .01
for a in air_rows:
if (min_lat <= df_airports.loc[a,lat2] <= max_lat) and (min_lon <= df_airports.loc[a,lon2] <= max_lon):
df_result['Type'] = 'Airport'
这里有两个示例数据框:
# Import pandas library
import pandas as pd
# initialize list of lists
data = [['NY', 'Uniondale', 'Nassau', '40.72', '-73.59'],
['NY', 'Uniondale', 'Nassau', '40.72', '-73.59'],
['NY', 'Uniondale', 'Nassau', '40.72', '-73.59'],
['NY', 'NY', 'New York', '40.76', '73.98'],
['NY', 'NY', 'New York', '40.76', '73.98']]
# Create the pandas DataFrame
df_result = pd.DataFrame(data, columns = ['state', 'city', 'county','latitude_fuze','longitude_fuze'])
# print dataframe.
df_result
还有……
data = [['New York', 'JFK', '40.64', '-73.78'],
['New York', 'JFK', '40.64', '-73.78'],
['Los Angeles', 'LAX', '33.94', '-118.41'],
['Chicago', 'ORD', '41.98', '-87.90'],
['San Francisco', 'SFO', '37.62', '-122.38']]
# Create the pandas DataFrame
df_airports = pd.DataFrame(data, columns = ['municipality_name', 'airport_code', 'latitude_air','longitude_air'])
# print dataframe.
df_airports
运行此代码时,我收到此错误:
KeyError: "None of [Float64Index([40.719515, 40.719515, 40.719515, 40.75682, 40.75682, 40.75682,\n 40.75682, 40.75682, 40.75682, 40.7646,\n ...\n 40.0006, 40.0006, 40.0006, 40.0006, 40.0006, 40.0006,\n 40.0006, 39.742417, 39.742417, 39.742417],\n dtype='float64', length=1720)] are in the [index]"
如果使用 KNN 或 Haversine 方法进行计算更好,我对此持开放态度。我不是在这里寻找距离,而是在纬度和经度数字上寻找相似之处。如果我确实需要计算距离以使其正常工作,请告诉我。谢谢大家。
【问题讨论】:
标签: python python-3.x latitude-longitude haversine