将String和Int快速存储在字典中

Question

我几乎是 Swift 的新手。 In this URL我会得到一些元素；其中一个元素是 categoryList，它本身有两个元素。我将goodTypeName设置为表格的单元格标题，当按下一个单元格时，它需要发送goodType，它是数字（Int）以放置在下一个Url中。我尝试创建字典，但失败了！

UiTable 代码:::

override func numberOfSections(in tableView: UITableView) -> Int {
    return 1
}
override func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
    return Global.GlobalVariable.names.count
}
override func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
    if Global.GlobalVariable.names == []
    {
        self.DisplayMessage(UserMessage: "nothing is available ")
        print("server is nil")
    }
    let cell = UITableViewCell()
    let content = Global.GlobalVariable.names[indexPath.row]
    cell.textLabel?.text = content
    cell.accessoryType = .disclosureIndicator
    return cell
}
override func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {
    print(indexPath.item)
    let next = self.storyboard?.instantiateViewController(withIdentifier: "SVC")
    self.navigationController?.pushViewController(next!, animated: true)
}

My problem is not with populating them in a table, my problem is when a cell is selected , goodtype is needed to be sent to next page, becuase next page's url has to have the goodtype code.

Answer 1

您可以使用“prepareSegue”来传递数据。

override func prepare(for segue: UIStoryboardSegue, sender: Any?) {

if segue.identifier == "something"{
    if let startViewController = segue.destination as? StartViewController{
        startViewController.goodtype = Global.GlobalVariable.goodtype[indexPath.row]
    }
}
}

在您的 StartViewController 中只需分配一个变量来接收您的数据：

var goodtype = String()

或使用导航控制器，但通过这一行，您可以访问另一个视图控制器属性。

         if let startViewController = storyboard.instantiateViewController(withIdentifier: "StartViewController") as? StartViewController {
    startViewController.goodtype = Global.GlobalVariable.goodtype[indexPath.row]
     let navigationController = UINavigationController()
  navigationController.pushViewController(startViewController, animated: true)
    }