将 json 数据发送到单独的类并显示在 tableView 上

Question

我目前正在将我的 json 数据发送到同一 ViewController 中的 Dictionary。我想将它发送到一个名为用户的类。数据显示在TableView 上。

import UIKit

class Users: NSObject {

    var name: String? 
}



class FriendsViewController: UIViewController, UITableViewDataSource, UITableViewDelegate {
     var userList = [Users]()

@IBOutlet weak var myTableView: UITableView!


final let urlString = "https://api.lookfwd.io/v1/test/users"

 var namesArray = [String]()

func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {

    return namesArray.count

}

func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
    let myCell = tableView.dequeueReusableCell(withIdentifier: "cell", for: indexPath) as! MyTableViewCell

    myCell.nameLabel.text = namesArray[indexPath.row]
    return myCell
}


override func viewDidLoad() {
    super.viewDidLoad()
   self.downloadJsonWithTask()


    // Do any additional setup after loading the view.
}

func downloadJsonWithTask() {

    let url = NSURL(string: urlString)

    var downloadTask = URLRequest(url: (url as URL?)!, cachePolicy: URLRequest.CachePolicy.reloadIgnoringCacheData, timeoutInterval: 20)

    downloadTask.httpMethod = "GET"

    URLSession.shared.dataTask(with: downloadTask, completionHandler: {(data, response, error) -> Void in

        let jsonData = try? JSONSerialization.jsonObject(with: data!, options: .allowFragments)

        if let dataArray = (jsonData! as AnyObject).value(forKey: "users") as? NSArray {
            for data in dataArray{


      //          let user = Users()

       //         user.setValuesForKeys(data as! [String : Any])

        //        self.userList.append(user)


             if let dataDict = data as? NSDictionary {
                    if let title = dataDict.value(forKey: "name") {
                       self.namesArray.append(title as! String)
                    }
                }
            print(jsonData!)
            }
        }
        OperationQueue.main.addOperation({
            self.myTableView.reloadData()
        })

        print(jsonData!)

    }).resume()
}

}

Answer 1

只需替换您的 downloadJsonWithTask 方法

    func downloadJsonWithTask() {

    let url = NSURL(string: urlString)

    var downloadTask = URLRequest(url: (url as URL?)!, cachePolicy: URLRequest.CachePolicy.reloadIgnoringCacheData, timeoutInterval: 20)

    downloadTask.httpMethod = "GET"

    URLSession.shared.dataTask(with: downloadTask, completionHandler: {(data, response, error) -> Void in

        if let response = data {
            if let jsonData = try? JSONSerialization.jsonObject(with: response, options: .allowFragments) as? [String:Any] {

                if let dataArray = (jsonData as AnyObject).value(forKey: "users") as? [[String:Any]] {
                    for data in dataArray{
                        let newUser = Users(data: data)
                        self.userList.append(newUser)
                        print(jsonData!)
                    }
                }
                OperationQueue.main.addOperation({
                    for use in self.userList {
                        print(use.name ?? "")
                    }

                    //reload your table here
                    // use name in cell for row at index as user.name
                })

                print(jsonData!)
            }
        }
    }).resume()
}

和你的User 模型：

class Users: NSObject {
var name: String?

init(data:[String:Any]) {
    super.init()
    if let nameStr = data["name"] as? String {
        self.name = nameStr
    }
}

}

尽量不要使用NSDictionary和NSArray，因为它们都是旧技术，使用新的[]，[:]

Answer 2

在Users类中，你需要传递json数据，并为类变量分配相应的数据。

import UIKit
class Users: NSObject {

    var name: String? 
   required init(dictionary: NSDictionary) {
    super.init()
    self.name = dictionary["name"] as? String ?? ""
}

}

您可以修改downloadJSONTask中将字典解析为的部分

if let dataDict = data as? NSDictionary {
                    let users = Users.init(dictionary: dataDict)
                    if let title = dataDict.value(forKey: "name") {

                       self.namesArray.append(title as! String)
                    }
}