带有部分模板的 TableView

Question

我关注了this Tutorial

而且效果很好。现在，如果我尝试从 JSON 中获取部分数据，这也可以正常工作，但是我在显示所有内容时遇到问题。

这就是我所做的：

//  TestVC.swift
//  WinterdienstTest
//
//  Created by zwipf on 09.02.17.
//  Copyright © 2017 Squirrel. All rights reserved.
//

import UIKit

class TestVC: UIViewController, UITableViewDataSource, UITableViewDelegate {

@IBOutlet weak var tableView: UITableView!

let sections: [String] = ["Tour 1", "Tour 2", "Tour 3"]
var adressTour1: [String] = []
var adressTour2: [String] = []
var adressTour3: [String] = []

var adressTourALL: [Int: [String]] = [:]


override func viewDidLoad() {
    super.viewDidLoad()

    tableView.delegate = self
    tableView.dataSource = self

    // URL abrufen
    let url = NSURL(string: "https://api.myjson.com/bins/mml65")
    let request = NSMutableURLRequest(url: url! as URL)
    let task = URLSession.shared.dataTask(with: request as URLRequest) { data,response,error in

    // JSON parsen und Ergebins in eine Liste von assoziativen Arrays wandeln
    let responseString = try! JSONSerialization.jsonObject(with: data!, options: .allowFragments) as! [String:Any]


    // Daten auslesen
    if let Liegenschaften = responseString["Liegenschaften"] as? [AnyObject] {

        for liegenschaft in Liegenschaften {

            if let Winterdienst = liegenschaft["Winterdienst"] as? [AnyObject] {

                for winterdienst in Winterdienst {

                    let tour = winterdienst["Tour"] as! String

                    if tour == "1" {

                        let adresse = liegenschaft["Adresse"] as! String
                        self.adressTour1.append(adresse)
                    }
                    if tour == "2" {

                        let adresse = liegenschaft["Adresse"] as! String
                        self.adressTour2.append(adresse)
                    }
                    if tour == "3" {

                        let adresse = liegenschaft["Adresse"] as! String
                        self.adressTour3.append(adresse)
                    }
                }
            }
        }
    }

    self.adressTourALL = [0:self.adressTour1, 1:self.adressTour2, 2:self.adressTour3]


    }

    // UI-Darstellung aktualisieren
    //OperationQueue.main.addOperation {
      //  self.tableView.reloadData()
    //}

    // task.resume()

    print(self.adressTourALL)


}



func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {

    return adressTourALL.count
}

func numberOfSections(in tableView: UITableView) -> Int {
    return sections.count
}

func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {

    var cell = tableView.dequeueReusableCell(withIdentifier: "cell")

    if cell == nil {
        cell = UITableViewCell(style: .default, reuseIdentifier: "cell");
    }

    print(adressTourALL[indexPath.section]![indexPath.row])
    cell!.textLabel!.text = adressTourALL[indexPath.section]![indexPath.row]

    return cell!
}

}

希望有人可以帮助我！

Answer 1

除其他外，您需要将其放入您的代码中：

func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
    switch section{
    case 0:
        return self.adressTour1.count
    case 1:
        return self.adressTour2.count
    case 2:
        return self.adressTour2.count
    default:
        return 1
}