将搜索栏单元格标签链接到视图控制器

Question

我正在尝试在 Xcode 中创建一个搜索栏，因此当您搜索一个项目时，您可以单击搜索结果单元格，它将转到视图控制器，但现在它所做的只是转到海景控制器并仅显示我单击的单元格的标签。

这是我的 .m 文件

@interface ListTableViewController () <UISearchDisplayDelegate>

@property (strong, nonatomic) NSArray *dataArray;
@property (strong, nonatomic) NSArray *searchResults;

@end

@implementation ListTableViewController

- (id)initWithStyle:(UITableViewStyle)style
{
self = [super initWithStyle:style];
if (self) {
    // Custom initialization
}
return self;
}

- (void)viewDidLoad
{
[super viewDidLoad];

self.dataArray = [NSArray arrayWithObjects:@"Tomb Raider", @"Little Big Planet",     @"Unchanted 3", @"BlackOps 2", nil];
}

- (void)didReceiveMemoryWarning
{
[super didReceiveMemoryWarning];
// Dispose of any resources that can be recreated.
}

- (void)filterContentForSearchText: (NSString *) searchText
{
NSPredicate *resultPredicate = [NSPredicate predicateWithFormat:@"SELF CONTAINS[cd] %@", searchText];
self.searchResults = [self.dataArray filteredArrayUsingPredicate:resultPredicate];
}

-(BOOL)searchDisplayController:(UISearchDisplayController *)controller shouldReloadTableForSearchString:(NSString *)searchString
{
[self filterContentForSearchText:searchString];
return YES;
}

#pragma mark - Table view data source

- (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView
{
return 1;
}

- (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:   (NSInteger)section
{
if (tableView == self.tableView) {
    return [self.dataArray count];
} else { // (tableView == self.searchDisplayController.searchResultsTableView)
    return  [self.searchResults count];
}

}

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
static NSString *CellIdentifier = @"Cell";
UITableViewCell *cell = [self.tableView dequeueReusableCellWithIdentifier:CellIdentifier forIndexPath:indexPath];

if (tableView == self.tableView) {
    cell.textLabel.text = [self.dataArray objectAtIndex:indexPath.row];
} else {
    cell.textLabel.text = [self.searchResults objectAtIndex:indexPath.row];
}
return cell;
}



#pragma mark - Table view delegate

-(void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
{
if ([segue.identifier isEqualToString:@"showDetails"]) {
    DetailsViewController *dvc = segue.destinationViewController;

    NSIndexPath *indexPath = nil;

    if ([self.searchDisplayController isActive]) {
        indexPath = [self.searchDisplayController.searchResultsTableView indexPathForSelectedRow];
        dvc.sendLabel = [self.searchResults objectAtIndex:indexPath.row];
        return;
    } else{
        indexPath = [self.tableView indexPathForSelectedRow];
        dvc.sendLabel = [self.dataArray objectAtIndex:indexPath.row];
        return;
    }
}
}


@end

谢谢，一切都会有帮助的。

Answer 1

你必须实现这个委托方法：

// Method returns the clicked row.
- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath {

   YourPushedViewController *ypVC = [[YourPushedViewController alloc] initWithNibName:@"YourPushedViewController" bundle:nil];
  ypVC.selectedText = myResultArray[indexPath.row]; 


   [self.navigationController pushViewController:ypVC animated:YES]; 

}

该方法是选择行并将选择的结果传递给另一个视图的响应。

这是给你的提示：Passing Data between View Controllers