【问题标题】:Alamofire API connection and SwiftAlamofire API 连接和 Swift
【发布时间】:2017-07-21 01:29:29
【问题描述】:

我在向 EatStreet API 发送 AlamoFire 请求时遇到问题。我有一个 API 密钥,并且我已经正确导入了 Alamofire。

https://developers.eatstreet.com/endpoint/search

下面是他们将为您创建 API URL 字符串的网站的链接。

尽管如此,我仍然没有成功

这是示例字符串

curl -X GET \
 -H 'X-Access-Token: __API_EXPLORER_AUTH_KEY__' \
 'https://api.eatstreet.com/publicapi/v1/restaurant/search?latitude=40.718293&longitude=-74.002276&method=pickup&pickup-radius=2'

下面是我的 api 和 Alamofire 请求的示例代码。对于结果的值,它不断返回 false。任何帮助表示赞赏

import UIKit
import Firebase
import FirebaseDatabase

import FirebaseAuth
import Alamofire
import SwiftyJSON

class ViewController: UIViewController {

override func viewDidLoad() {
    super.viewDidLoad()

    // Do any additional setup after loading the view, typically from a nib.
    let tap: UITapGestureRecognizer = UITapGestureRecognizer(target: self, action: #selector(LoginViewController.dismissKeyboard))

    //Uncomment the line below if you want the tap not not interfere and cancel other interactions.
    tap.cancelsTouchesInView = false

    view.addGestureRecognizer(tap)

    let apiToContact = "\\ -H 'X-Access-Token: f6565a0360167144' \\'https://api.eatstreet.com/publicapi/v1/restaurant/search?latitude=40.718293&longitude=-74.002276&method=pickup&pickup-radius=2'"
    Alamofire.request(apiToContact).validate().responseJSON() { response in
        switch response.result {
        case .success:
            if let value = response.result.value {
                let json = JSON(value)

                // Do what you need to with JSON here!
                // The rest is all boiler plate code you'll use for API requests
                print(json)

            }
        case .failure(let error):
            print(error)
        }
    }


}


//Calls this function when the tap is recognized.
func dismissKeyboard() {
    //Causes the view (or one of its embedded text fields) to resign the first responder status.
    view.endEditing(true)
}

override func didReceiveMemoryWarning() {
    super.didReceiveMemoryWarning()
    // Dispose of any resources that can be recreated.
}


}

【问题讨论】:

    标签: swift alamofire


    【解决方案1】:

    Alamofire Docs 中所述,您应该发送带有标头参数的请求

    let headers: HTTPHeaders = [
        "X-Access-Token": "API_EXPLORER_AUTH_KEY"
    ]
    
    let url = "https://api.eatstreet.com/publicapi/v1/restaurant/search?latitude=40.718293&longitude=-74.002276&method=pickup&pickup-radius=2"
    
    Alamofire.request(url, headers: headers).responseJSON { response in
        print(response)
    }
    

    【讨论】:

    • @HiDungLing 很好,请标记为正确答案 ;)
    【解决方案2】:

    另一种解决方案如下所示。这里会自动生成查询参数并附加到 URL。这种方法可以防止查询参数中的一些特殊字符转义。试试下面的

     func sendRequest() {
        let headers = ["X-Access-Token":"eatstreetToken"]
        let parameters:[String:Any] = ["latitude":40.718293,"longitude":-74.002276, "method":"pickup","pickup-radius":2]
        let apiToContact = "https://api.eatstreet.com/publicapi/v1/restaurant/search"
    
        let request = Alamofire.request(apiToContact, method: .get, parameters: parameters, encoding: URLEncoding.queryString, headers: headers)
        request.validate().responseJSON() { response in
            print(response.response?.url ?? "malformed url")
            switch response.result {
            case .success(let value):
                  print(value)
            case .failure(let error):
                print(error)
            }
        }
    }
    

    【讨论】:

    • 如果我希望编码为 json 怎么办
    • 看起来不像eatstreet为该字符串返回的内容
    • 我刚刚通过在eatstreet开发者门户上创建新帐户自己尝试了上述代码,并且打印在我的控制台上的响应是正确的
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