JSON数据操作

Question

我正在尝试将变量传递到 JSON 值中，以便使用 Alamofire 在发布请求中发送。第一个示例是 JSON 值的外观，但是当传递变量时，JSON 实际上看起来像第二个示例。有谁知道出了什么问题，或者如何解决这个问题？

正确的 JSON：

{   "gender": "male",   
    "dob": "08 Jul 2001",   
    "loyalty_points": "2",  
    "barber_type": "1",     
    "account": {        
        "first_name": "Bob",        
        "last_name": "Smith",       
        "email": "bob@live.com",        
        "password": "1234",         
        "timestamp": "2016-07-08 20:26:13 +0000"    
    } 
}

不正确的 JSON：

[  "loyalty_points": 0, 
   "account": {
       email = "bob@live.com";
       "first_name" = Bob;
       "last_name" = Smith;
       password = 1234;
       timestamp = "2016-07-08 20:26:13 +0000";
   }, 
   "gender": Male, 
   "barber_type": 2, 
   "dob": 08 Jul 2001
]

Swift 代码：

let account: [String: AnyObject] = [ "first_name": firstName!, "last_name": lastName!, "email": email!, "password": password!, "timestamp": NSDate()]

let parameters: [String: AnyObject] = [ "gender": gender!, "dob": date!, "loyalty_points": "0", "barber_type": barberType!, "account": account]

Alamofire.request(.POST, "api.exampledomain.co.uk/v1/user";, parameters: parameters as? [String : AnyObject], encoding: .JSON) 

Answer 1

Alamofire 使用的底层NSJSONSerialization.dataWithJSONObject() 函数无法将NSDate() 对象转换为合法的JSON，当你尝试时会抛出异常。

因此，您需要先将该timestamp 对象转换为字符串值，然后将其添加到account 对象中。

import Foundation

let firstName: String? = "Bob"
let lastName: String? = "Smith"
let email: String? = "bob@live.com"
let password: String? = "1234"

var formatter: NSDateFormatter = NSDateFormatter()
formatter.dateFormat = "Y-MM-dd H:mm:ss +0000"
let nsdateString: String = formatter.stringFromDate(NSDate())

let account: [String: AnyObject] = [
    "first_name": firstName!,
    "last_name": lastName!,
    "email": email!,
    "password": password!,
//  "timestamp": NSDate()    // <-- causes an exception if uncommented
    "timestamp": nsdateString   // already converted to string
]

let gender: String? = "Male"
let date: String? = "08 Jul 2001"
let barberType: String? = "1"

let parameters: [String: AnyObject] = [ "gender": gender!, "dob": date!, "loyalty_points": "0", "barber_type": barberType!, "account":

let data = try NSJSONSerialization.dataWithJSONObject(parameters, options: .PrettyPrinted)
let str = String(data: data, encoding: NSUTF8StringEncoding)

print(str!)

带输出：

{
  "loyalty_points" : "0",
  "account" : {
    "first_name" : "Bob",
    "last_name" : "Smith",
    "email" : "bob@live.com",
    "password" : "1234",
    "timestamp" : "2016-07-08 22:02:50 +0000"
  },
  "gender" : "Male",
  "barber_type" : "1",
  "dob" : "08 Jul 2001"
}

Answer 2

如果您希望每个人的信息采用相同的格式，看起来就像您所做的那样，那么当您可以使用 string 时，不要在 arrays 上浪费时间。

Swift 示例代码：

let gender = "Male"           // Test data
let date = "08 Jul 2001"
let loyalty_points = 0
let barberType = 1
let firstName = "Bob"
let lastName = "Smith"
let email = "bob@live.com"
let password = "1234"

let jsonstring = "{\t\"gender\": \"\(gender)\",\n\t\"dob\": \"\(date)\",   \n\t\"loyalty_points\": \"\(loyalty_points)\",\n\t\"barber_type\": \"\(barberType)\",\t \n\t\"account\": {\t\t\n\t\t\"first_name\": \"\(firstName)\",\t\t\n\t\t\"last_name\": \"\(lastName)\",\t\n\t\t\"email\": \"\(email)\",\t\t\n\t\t\"password\": \"\(password)\",\t\t \n\t\t\"timestamp\": \"\(NSDate())\"\t\n\t}\n}"

print(jsonstring)    // Output the JSON code

结果：

{   "gender": "Male",   
    "dob": "08 Jul 2001",   
    "loyalty_points": "0",  
    "barber_type": "1",  
    "account": {        
        "first_name": "Bob",        
        "last_name": "Smith",      
        "email": "bob@live.com",        
        "password": "1234",      
        "timestamp": "2016-07-08 17:18:34 +0000"    
    } 
}