【问题标题】:URL Encode Alamofire GET params with SwiftyJSON使用 SwiftyJSON 对 Alamofire GET 参数进行 URL 编码
【发布时间】:2015-09-15 20:59:17
【问题描述】:

我试图让 Alamofire 在 GET 请求中发送以下参数,但它发送的是乱码:

filters={"$and":[{"name":{"$bw":"duke"},"country":"gb"}]}
//www.example.com/example?filters={"$and":[{"name":{"$bw":"duke"},"country":"gb"}]}
//Obviously URL encoded

这是我的代码:

let jsonObject = ["$and":[["name":["$bw":string], "country":"gb"]]]
let json = JSON(jsonObject)
print(json)

输出

{ “$和”:[ { “姓名” : { “$bw”:“公爵” }, “国家”:“国标” } ] }

这是我的参数请求:

let params = ["filters" : json.rawValue, "limit":"1", "KEY":"my_key"]

这是 AlamoFire 发送的内容:

KEY=my_key&
filters[$and][][country]=gb&
filters[$and][][name][$bw]=duke&
limit=1 

如您所见,过滤器参数完全是一团糟。我做错了什么?

【问题讨论】:

  • 您能在这里复制一下您是如何使用 Alamofire 发送此请求的吗?这个请求不是使用 GET 发送的吗?也许您可以尝试使用 POST 方法?
  • 必须得到。我用.request(.GET, url, params)

标签: ios swift alamofire swifty-json


【解决方案1】:

默认情况下,Alamofire 使用 POST 正文中的参数列表对参数进行编码。尝试将编码更改为JSON。这样,Alamofire 将按照您的预期将字典序列化为 JSON 字符串:

let parameters = [
    "foo": [1,2,3],
    "bar": [
        "baz": "qux"
    ]
]

Alamofire.request(.POST, "http://httpbin.org/post", parameters: parameters, encoding: .JSON)
// HTTP body: {"foo": [1, 2, 3], "bar": {"baz": "qux"}}

或使用您的代码:

let string = "duke"
let jsonObject = ["$and":[["name":["$bw":string], "country":"gb"]]]
let json = JSON(jsonObject)
let params = ["filters" : json.rawValue, "limit":"1", "KEY":"my_key"]

Alamofire.request(.POST, "http://httpbin.org/post", parameters: params, encoding: .JSON)
    .responseString(encoding: NSUTF8StringEncoding) { request, response, content, error in
        NSLog("Request: %@ - %@\n%@", request.HTTPMethod!, request.URL!, request.HTTPBody.map { body in NSString(data: body, encoding: NSUTF8StringEncoding) ?? "" } ?? "")
        if let response = response {
            NSLog("Response: %@\n%@", response, content ?? "")
        }
}

获取输出:

Request: POST - http://httpbin.org/post
{"filters":{"$and":[{"name":{"$bw":"duke"},"country":"gb"}]},"limit":"1","KEY":"my_key"}

编辑:GET 参数中的 URL 编码 JSON

如果您想在 GET 参数中发送一个 URL 编码的 JSON,您必须首先生成 JSON 字符串,然后将其作为字符串传递到您的参数字典中:

SWIFT 1

let string = "duke"
let jsonObject = ["$and":[["name":["$bw":string], "country":"gb"]]]
let json = JSON(jsonObject)

// Generate the string representation of the JSON value
let jsonString = json.rawString(encoding: NSUTF8StringEncoding, options: nil)!
let params = ["filters" : jsonString, "limit": "1", "KEY": "my_key"]


Alamofire.request(.GET, "http://httpbin.org/post", parameters: params)
    .responseString(encoding: NSUTF8StringEncoding) { request, response, content, error in
        NSLog("Request: %@ - %@\n%@", request.HTTPMethod!, request.URL!, request.HTTPBody.map { body in NSString(data: body, encoding: NSUTF8StringEncoding) ?? "" } ?? "")
        if let response = response {
            NSLog("Response: %@\n%@", response, content ?? "")
        }
}

SWIFT 2

let string = "duke"
let jsonObject = ["$and":[["name":["$bw":string], "country":"gb"]]]
let json = JSON(jsonObject)

// Generate the string representation of the JSON value
let jsonString = json.rawString(NSUTF8StringEncoding)!
let params = ["filters" : jsonString, "limit": "1", "KEY": "my_key"]

Alamofire.request(.GET, "http://httpbin.org/post", parameters: params)
    .responseString(encoding: NSUTF8StringEncoding) { request, response, result in
        NSLog("Request: %@ - %@\n%@", request!.HTTPMethod!, request!.URL!, request!.HTTPBody.map { body in NSString(data: body, encoding: NSUTF8StringEncoding) ?? "" } ?? "")
        switch result {
        case .Success(let value):
            NSLog("Response with content: %@", value)
        case .Failure(let data, _):
            NSLog("Response with error: %@", data ?? NSData())
        }
}

SWIFT 3 和 Alamofire 4.0

let string = "duke"
let jsonObject = ["$and":[["name":["$bw":string], "country":"gb"]]]
let json = JSON(jsonObject)

// Generate the string representation of the JSON value
let jsonString = json.rawString(.utf8)!
let params = ["filters" : jsonString, "limit": "1", "KEY": "my_key"]

Alamofire.request("http://httpbin.org/post", method: .get, parameters: params)
    .responseString { response in
        #if DEBUG
            let request = response.request
            NSLog("Request: \(request!.httpMethod!) - \(request!.url!.absoluteString)\n\(request!.httpBody.map { body in String(data: body, encoding: .utf8) ?? "" } ?? "")")
            switch response.result {
            case .success(let value):
                print("Response with content \(value)")
            case .failure(let error):
                print("Response with error: \(error as NSError): \(response.data ?? Data())")
            }
        #endif
}

这会生成一个带有以下 URL 的 GET 请求:

http://httpbin.org/post?KEY=my_key&filters=%7B%22%24and%22%3A%5B%7B%22name%22%3A%7B%22%24bw%22%3A%22duke%22%7D%2C%22country%22%3A%22gb%22%7D%5D%7D&limit=1

那个 URL-Decoded 是:

http://httpbin.org/post?KEY=my_key&filters={"$and":[{"name":{"$bw":"duke"},"country":"gb"}]}&limit=1

【讨论】:

  • 谢谢(我应该在问题中指定抱歉)但我需要做一个获取请求。它还需要看起来像这样: "filters":"{"$and":[{"name":{"$bw":"duke"},"country":"gb"}]}","limit ":"1","KEY":"my_key".... 不知道是谁写的 API... 我会在问题中说得更清楚。
  • 因此您需要一个 JSON 字符串作为 GET URL 中的 URL 编码参数。这完全改变了这个问题。查看我的编辑,看看是否符合您的需求。
  • 谢谢,太好了!我必须编辑的一件事是let jsonString = json.rawString(NSUTF8StringEncoding, options: .PrettyPrinted)!,因为你不能提供nil,而且第一个标签是无关的。我将对其进行编辑并编辑问题以使其他人更清楚。
  • @MobileBloke 添加了 Swift 3 版本
  • 我在 swift 上看到的更好的帖子之一,感谢发帖。
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