如何在 swift4 中使用 Rxalamofire 发送 URL 请求

Question

实际上我是 iOS 新手，现在我的任务是使用 Rxalamofire 发送 URL 请求。我完全不知道 Rxalamofire。以前我只使用 alamofire。以前我只使用 alamofire。现在我也像以前使用以前一样发送了 url 请求，但后来我发现 Rxalamofire 比 alamofire 好得多。不幸的是我无法发送 URL 请求。所以，谁能告诉我一步一步的过程。在此先感谢。

 postParameters = ["username":mailid,"password":password]

            Alamofire.request(Constants.loginapi, method: .post, parameters: postParameters, encoding: URLEncoding.default, headers: nil).responseJSON {  response in
                switch response.result {
                case .success:
                    print(response)
                  case .failure(let error):
                    print(error)
                }

            }

Answer 1

我看到你之前的帖子在 MVVM/RxSwift 上苦苦挣扎。

你可以在这里找到一个可以帮助你关注的项目-

1. RXSwift + MVVM
2. Rxswift + Alamofire

https://github.com/saurabh-360/RxAlamofireDemo

对于问题，您可以通过标准方式发送请求，

但是在使用 RXswift API 时，使用 Observable 模式是更好的方法，它是观察数据流。

以下代码可以帮助您入门。

func loginUser() -> Observable<Any>? {

    return Observable<Any>.create({observer in
        /**
         parameters or additional headers we can bind with the url request
         the case is standard here like we do in URLSession requests
         consider this example to incorporate the same
         https://stackoverflow.com/a/40608923/4549304
         */
        let parameters:[String:String] = ["username":"Your username value here",
                                          "password":"Your password value here"]

        /**
         There are multiple ways to request data from the servers using
         Default ALamofire methods
         I am using Alamofire.request(String) method here for the same.


         We Can also use
         request(_ urlRequest: URLRequestConvertible)
         method in case we want to make a post request
         with additional headers and parameters

         */

        Alamofire.request("https://reqres.in/api/login", method: .post, parameters: parameters, encoding: JSONEncoding.default, headers: nil)
            .response { response in
                if response.response?.statusCode == 400 {
                    print("authorisation error")

                    // you need to exit the request here since there was error and
                    // no parsing is needed further for the response
                    // you can also send and error using the observer.OnError(Error)
                    return observer.onCompleted()
                }

                // convert data to our model and update the local variable
                guard let responseData =  response.data else {
                    return observer.onCompleted()
                }
                do {
                    let model = try JSONDecoder().decode(YourModel.self, from: responseData)
                    observer.onNext(model)
                    observer.onCompleted()
                }catch {
                    observer.onError(error)
                    observer.onCompleted()
                    print("some thing went wrong.")
                }
        }

        return Disposables.create();
    })
}