【发布时间】:2016-04-19 05:37:36
【问题描述】:
在我的应用中,我实现了推送通知。当我的应用程序处于运行状态时,如果推送通知来了,我将使用此代码处理。
func application(application: UIApplication, didReceiveRemoteNotification userInfo: [NSObject : AnyObject]) {
print(userInfo)
myid = (userInfo["id"] as? String)!
print(myid)
if let notification = userInfo["aps"] as? NSDictionary,
let alert = notification["alert"] as? String {
var alertCtrl = UIAlertController(title: "Notification", message: alert as String, preferredStyle: UIAlertControllerStyle.Alert)
alertCtrl.addAction(UIAlertAction(title: "OK", style: UIAlertActionStyle.Default, handler: nil))
// Find the presented VC...
var presentedVC = self.window?.rootViewController
while (presentedVC!.presentedViewController != nil) {
presentedVC = presentedVC!.presentedViewController
}
presentedVC!.presentViewController(alertCtrl, animated: true, completion: nil)
}
我想要什么 :: 当我的应用程序未运行并且如果推送通知来了,我想根据该通知帖子 ID 打开特定帖子。那么我该怎么做呢? 这是我的代码
func application(application: UIApplication, didFinishLaunchingWithOptions launchOptions: [NSObject: AnyObject]?) -> Bool {
SVProgressHUD.setDefaultMaskType(SVProgressHUDMaskType.Black)
UIApplication.sharedApplication().applicationIconBadgeNumber = 0
let dicTemp = launchOptions?["UIApplicationLaunchOptionsRemoteNotificationKey"]
if dicTemp != nil{
window = UIWindow(frame: UIScreen.mainScreen().bounds)
storyboard = UIStoryboard(name: "Main", bundle: nil)
myid = (dicTemp["id"] as? String)!
let controller:pushnotificationpostViewController = self.storyboard.instantiateViewControllerWithIdentifier("pushnotificationpostViewController") as! pushnotificationpostViewController
navigation = UINavigationController(rootViewController: controller)
window?.rootViewController = navigation
window?.makeKeyAndVisible()
}
else
{
window = UIWindow(frame: UIScreen.mainScreen().bounds)
storyboard = UIStoryboard(name: "Main", bundle: nil)
let controller:MainViewController = self.storyboard.instantiateViewControllerWithIdentifier("MainViewController") as! MainViewController
navigation = UINavigationController(rootViewController: controller)
window?.rootViewController = navigation
window?.makeKeyAndVisible()
}
//print(NSUserDefaults.standardUserDefaults().valueForKey("pushnotify")as! Bool)
let notificationTypes: UIUserNotificationType = [UIUserNotificationType.Alert, UIUserNotificationType.Badge, UIUserNotificationType.Sound]
let pushNotificationSettings = UIUserNotificationSettings(forTypes: notificationTypes, categories: nil)
application.registerUserNotificationSettings(pushNotificationSettings)
if (NSUserDefaults.standardUserDefaults().valueForKey("pushnotify")) != nil
{
pushnotification = NSUserDefaults.standardUserDefaults().valueForKey("pushnotify") as! Bool
// let notificationcheck = NSUserDefaults.standardUserDefaults().valueForKey("pushnotify") as! Bool
if (pushnotification == true)
{
application.registerForRemoteNotifications()
}
else
{
application.unregisterForRemoteNotifications()
}
}
else
{
application.registerForRemoteNotifications()
}
return true
}
但是通过这段代码,我没有得到 id 意味着 myid 变得为零。那我该怎么做呢?
【问题讨论】:
-
您的代码在应用运行时是否有效?
-
是的,它在应用程序运行时工作@SuhasPatil
标签: ios swift push-notification swift2 ios9