执行动作按下通知 Swift

Question

我正在使用 Firebase 通知来发送和接收 RemoteNotification。

当我收到通知时，我还会收到一个 ID，让我可以识别特定的“帖子”。

现在，当我点击通知时，我需要该应用打开一个 viewController 并传递接收到的 ID，以便启动一个加载“发布”信息的方法（在 viewDidLoad() 中）。

这是通知的代码：

    func application(_ application: UIApplication, didReceiveRemoteNotification userInfo: [AnyHashable: Any],
                 fetchCompletionHandler completionHandler: @escaping (UIBackgroundFetchResult) -> Void) {
    // Print message ID.
    print("Message ID: \(userInfo["gcm.message_id"]!)")

    let aps = userInfo["aps"] as! NSDictionary
    let body_notifica = aps["alert"]! as! NSDictionary
    let titolo_notifica = body_notifica["title"]! as! String
    let testo_notifica = body_notifica["body"]! as! String

    let id_lavoro = userInfo["id_lavoro"]! //THIS IS THE ID I NEED TO PASS TO VIEW CONTROLLER

    if application.applicationState == UIApplicationState.inactive || application.applicationState == UIApplicationState.background{
        let viewController = self.window!.rootViewController!.storyboard!.instantiateViewController(withIdentifier: "annuncio_view_controler")
        viewController.performSegue(withIdentifier: "a", sender: <#T##Any?#>)
    }


    let banner = Banner(title: titolo_notifica, subtitle: testo_notifica, image: UIImage(named: "Info"), backgroundColor: UIColor(red:0.0/255.0, green:0.0/255.0, blue:0.0/255.0, alpha:0.5))
    banner.dismissesOnTap = true
    banner.show(duration: 3.0)

    print(userInfo)

}

谢谢你们！

Answer 1

感谢@Vadim Kozak

 if application.applicationState == UIApplicationState.inactive || application.applicationState == UIApplicationState.background{
        guard let rootViewController = self.window?.rootViewController as? UITabBarController else {
            return
        }
        // select second tab
        rootViewController.selectedIndex = 1

        guard let navigationController = rootViewController.selectedViewController as? UINavigationController else {
            return
        }


        let viewController = self.window!.rootViewController!.storyboard!.instantiateViewController(withIdentifier: "annuncio_view_controler") as! LavoroViewController

        viewController.id_lavoro = id_lavoro!

        rootViewController.present(viewController, animated: true, completion: nil)


    }

Answer 2

您可以使用此代码示例来处理此问题

func application(_ application: UIApplication, didReceiveRemoteNotification userInfo: [AnyHashable: Any], fetchCompletionHandler completionHandler: @escaping (UIBackgroundFetchResult) -> Void) {


    if ( application.applicationState == .inactive || application.applicationState == .background){

        //handle tapping on push notification and here you can open needed controller
    }
}

要确切知道需要打开哪个控制器，需要查看控制器层次结构

在我的情况下

   `guard let rootViewController = self.window?.rootViewController as? TabBarVC else {
        return
    }
    // select second tab
    rootViewController.selectedIndex = 1

    guard let navigationController = rootViewController.selectedViewController as? UINavigationController else {
        return
    }

`

编辑：我试过这个，但没有。

if application.applicationState == UIApplicationState.inactive || application.applicationState == UIApplicationState.background{
        let viewController = self.window!.rootViewController!.storyboard!.instantiateViewController(withIdentifier: "home_view_controller") as! HomeViewController

        viewController.toPassId = id_lavoro!
        viewController.performSegue(withIdentifier: "segue_annuncio_profilo", sender: self)

    }

如何检查层次结构？我的视图不是 TabBar 的视图，它可以从很多视图中打开（也留在 TabBar 中）