当用户在 swift 中单击推送通知时打开自定义 url

Question

我正在尝试使用 WKWebView 和 Firebase Push 开发 IOS / Swift 应用程序。我想使用 PHP 发送通知，当用户单击通知以在 webview 中打开自定义 URL 时。默认网址是

let url = URL(string: "https://mywebsite.com/index.php?token=\(token)")!

我想在这个 url 中传递一个像这样的 id

let url = URL(string: "https://client.gazduire.net/app3/index.php?token=\(token)&ntid=(id that is send with push notification, ex.:1)")!

我在 appdelegate.swift 中的代码

 func userNotificationCenter(_ center: UNUserNotificationCenter,didReceive response: UNNotificationResponse,
withCompletionHandler completionHandler: @escaping () -> Void) {
let userInfo = response.notification.request.content.userInfo
// Print message ID.
if let messageID = userInfo[gcmMessageIDKey] {
  print("Message ID: \(messageID)")
}
// Print full message.
print(userInfo)

let notificationName = Notification.Name("test")
NotificationCenter.default.post(name: notificationName, object: nil,userInfo: userInfo)

let ntid = userInfo["ntid"] as! String
print("\(ntid)")


completionHandler()

}

ViewController.swift

@objc func test() {
    let appDelegate = UIApplication.shared.delegate as! AppDelegate
    let ntid = appDelegate.ntid
    let token = Messaging.messaging().fcmToken


guard let url = URL(string: "https://mywebsite.com/index.php?token=\(token ?? "")&ntid=\(ntid)")      else {
   print("Invalid URL")
   return
   }

    let request = URLRequest(url: url)
    webView.load(request)
}

当用户点击推送通知时，我可以将 ntid（ntid 已接收并且打印正常）从 appdelegate 发送到 viewcontroller 吗？谢谢！

Answer 1

简单来说，只需在视图控制器的层次结构中找到您的视图控制器，将“ntid”值传递给存储的属性并调用“test”方法。

Answer 2

首先定义枚举为

enum Identifiers {
  static let viewAction = "cat1"
  static let newsCategory = "cat2"
}

然后在你的 UNUserNotificationCenterDelegate 中

extension AppDelegate: UNUserNotificationCenterDelegate {
  func userNotificationCenter(
    _ center: UNUserNotificationCenter,
    didReceive response: UNNotificationResponse,
    withCompletionHandler completionHandler: @escaping () -> Void) {

    // 1
    let userInfo = response.notification.request.content.userInfo

    // 2
    if let aps = userInfo["aps"] as? [String: AnyObject],
      let newsItem = NewsItem.makeNewsItem(aps) {

      (window?.rootViewController as? UITabBarController)?.selectedIndex = 1

      // 3
      if response.actionIdentifier == Identifiers.viewAction,
        let url = URL(string: newsItem.link) {
        let safari = SFSafariViewController(url: url)
        window?.rootViewController?.present(safari, animated: true,
                                            completion: nil)
      }
    }

    // 4
    completionHandler()
  }
}

像这样在推送服务中添加类别

{
  "aps": {
    "alert": "messaga",
    "sound": "default",
    "link_url": "www.google.com",
    "category": "cat1",

  }
}

它将检查 aps 类型，然后如果类别类型为 1 或 2，则推送视图控制器。 你可以通过这种方式添加很多你想要的