XMPPFramework - 如何获取在线和离线好友列表？

Question

如何在 iOS 中使用 XMPPFramework 获取在线和离线好友列表？

我想向用户发送好友请求。那么我该如何实现呢？有人可以为我分享一些示例代码吗？

谢谢。

Answer 1

通过使用这些方法，您将收到整个用户在线/离线、添加、删除、更新等的通知。通过使用这些方法，您可以更新您的联系人列表

- (void)xmppRoster:(XMPPRosterMemoryStorage *)sender didAddUser:(XMPPUserMemoryStorageObject *)user

- (void)xmppRoster:(XMPPRosterMemoryStorage *)sender didUpdateUser:(XMPPUserMemoryStorageObject *)user

- (void)xmppRoster:(XMPPRosterMemoryStorage *)sender didRemoveUser:(XMPPUserMemoryStorageObject *)user

- (void)xmppRoster:(XMPPRosterMemoryStorage *)sender
    didAddResource:(XMPPResourceMemoryStorageObject *)resource
          withUser:(XMPPUserMemoryStorageObject *)user

- (void)xmppRoster:(XMPPRosterMemoryStorage *)sender
 didUpdateResource:(XMPPResourceMemoryStorageObject *)resource
          withUser:(XMPPUserMemoryStorageObject *)user

- (void)xmppRoster:(XMPPRosterMemoryStorage *)sender
 didRemoveResource:(XMPPResourceMemoryStorageObject *)resource
          withUser:(XMPPUserMemoryStorageObject *)user

// 添加好友

- (void)addContactWithUserName:(NSString *)userName andNickName:(NSString *)nickName;
{
    if(userName)
    {
        XMPPJID *jid = [XMPPJID jidWithString:[NSString stringWithFormat:@"%@@%@",userName,self.hostName]];
        if(nickName)
        {
            [_xmppRoster addUser:jid withNickname:nickName];
        }
        else
        {
            [_xmppRoster addUser:jid withNickname:nil];
        }
    }
else
{
    NSLog(@"missing userName");
}
}