raw_input() 带有“if....in..”语句

Question

我正在尝试编写一个需要用户输入的小游戏。

while True:
    x = raw_input("\n> ")

    if x in ["Susan", "Foreman"] and not grand_name: 
        print "The button glows! You have guessed the password! You can press the button now"
        grand_name = True
    elif x in ["Press", "press", "button"] and not grand_name:
        print "You have to guess the password first!"
    elif x in ["Press", "press", "button"] and grand_name:
        print "The TARDIS materializes around the Doctor! He has been freed from a gaseous monster!"
        end()
    else:
        print "Try Again."

我想让用户可以键入“按下按钮”或“我按下按钮”来满足所需的 elif 语句，而不是必须准确地键入列表的对象。如果单词本身在输入中的任何位置，我只想运行该语句。有没有一种方法可以让 Python 识别输入是否包含列表中的单词而无需准确输入单词？我希望这是有道理的。这是我问的第一个问题，所以我还在学习。谢谢。

我尝试使用如下示例中的 any()，但它返回错误“未定义全局名称 w”

当真时： x = raw_input("\n> ") opt1 = [“苏珊”，“工头”] opt2 = ["按下", "按下", "按钮"]

    if any(z in x for z in opt1): 
        print "The button glows! You have guessed the password! You can press the button now"
        grand_name = True
    elif any(w in x for w in opt2) and not grand_name:
        print "You have to guess the password first!"
    elif any(w in x for x in opt2) and grand_name:
        print "The TARDIS materializes around the Doctor! He has been freed from a gaseous monster!"
        end()
    else:
        print "Try Again."

Answer 1

你是说if "press" in x.lower() or "button" in x.lower()？

>>> "press" in "some sentence with the word press in it"
True

>>> words = ["press","button","otherword"]
>>> any(w in "aaa press bbb" for w in words)
True
>>> any(w in "aaa button bbb" for w in words)
True
>>> any(w in "aaa bbb" for w in words)
False