通过 segue 将 NSString 值分配给 UI 标签文本

Question

所以我想有一个字符串 @"Welcome%@!"被标记到我的指针 *name 上，因此如果用户在 UI 标签文本上输入名称，它可以被转到下一页，并且还会在名称上附加问候语“Welcome”。我的代码如下：

@property (weak, nonatomic) IBOutlet UITextField *nameTextField;

-(void) prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
{
if ([segue.identifier isEqualToString:@"setName:"]) {
    if ([segue.destinationViewController respondsToSelector:@selector(setName:)]) {
        NSString *name = self.nameTextField.text;
        [segue.destinationViewController performSelector:@selector
         (setName:) withObject:name];
    }
}
}
Next Page “Second View Controller.m” :

@interface SecondViewController () @property (weak, nonatomic) IBOutlet UILabel *nameLabel; @implementation SecondViewController

-(void)setName: (NSString *)name
{
    _name = name;
    self.nameLabel.text = self.name;

}

谁能告诉我如何输入一个字符串，以便将其与 (NSString *)name 一起标记

谢谢

Answer 1

了解Formatting String Objects。以下是我的回答：

- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
{
    if ([segue.identifier isEqualToString:@"setName:"]) {
        if ([segue.destinationViewController respondsToSelector:@selector(setName:)]) {
            NSString *name = self.nameTextField.text;
            SecondViewController *secondCtrl = [segue destinationViewController];
            [secondCtrl setName:name];
        }
    }
}

在您的 SecondViewController 中：

@interface SecondViewController () 
@property (weak, nonatomic) IBOutlet UILabel *nameLabel; 
@end

@implementation SecondViewController

- (void)setName:(NSString *)name
{
    _name = name;
    self.nameLabel.text = [NSString stringWithFormat:@"Welcome %@", self.name];
}

@end