iOS 8 [UIApplication sharedApplication].scheduledLocalNotifications 为空

Question

我正在尝试将我的应用程序更新到 iOS 8。在一个函数中，我以这种方式安排了本地通知（我已经检查了 firedate 和通知的所有其他部分是否正确）：

[[UIApplication sharedApplication] scheduleLocalNotification:localNotification];

然后我使用此代码打印预定的本地通知：

NSLog(@"notifications %@", [UIApplication sharedApplication].scheduledLocalNotifications );

但数组

[UIApplication sharedApplication].scheduledLocalNotifications 

即使没有触发通知也是空的。 然后，为了检查本地通知是否真的安排好了，我尝试使用代码

NSLog(@"notification appdelegate %@", application.scheduledLocalNotifications );

在函数中

- (void)applicationWillResignActive:(UIApplication *)application 

Appdelegate.m 在这种情况下，计划的本地通知数组不为空，NSLog 函数打印正确的通知。这只发生在真实设备上，在模拟器中我的应用程序运行良好。问题不在于检查用户安排本地通知的权限，因为我已经遇到过。有人可以帮助我吗？有什么想法吗？

Answer 1

这不是 iOS 8 的问题，而是

[UIApplication sharedApplication].scheduledLocalNotifications

问题。我找到的最相关的答案here

现在有类似的问题。我的猜测是iOS没有 立即安排通知，但仅在结束时 当前运行循环。我在设置时遇到了这些问题 scheduleLocalNotifications 属性在同一运行中多次 循环和更改似乎没有相应更新。我想我会 自己保留一份本地通知数组的副本，只设置 scheduleLocalNotifications 并且从不阅读它。

Answer 2

对于 iOS8 ：

从现在起 30 秒后触发本地通知。

- 用于目标 c

    UILocalNotification *localNotification = [[UILocalNotification alloc] init];
    localNotification.alertAction = @"Testing notifications on iOS8";
    localNotification.alertBody = @"Woww it works!!";
    localNotification.fireDate = [NSDate dateWithTimeIntervalSinceNow: 30];
    [[UIApplication sharedApplication] scheduleLocalNotification:localNotification];

- 斯威夫特

    var localNotification:UILocalNotification = UILocalNotification()
    localNotification.alertAction = "Testing notifications on iOS8"
    localNotification.alertBody = "Woww it works!! 
    localNotification.fireDate = NSDate(timeIntervalSinceNow: 30)
    UIApplication.sharedApplication().scheduleLocalNotification(localNotification)

注册通知设置

- 用于目标 c

    - (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions
    {
        [application registerUserNotificationSettings:[UIUserNotificationSettings settingsForTypes:UIUserNotificationTypeAlert|UIUserNotificationTypeBadge|UIUserNotificationTypeSound categories:nil]]

        return YES;
    }

- 斯威夫特

    func application(application: UIApplication, didFinishLaunchingWithOptions launchOptions: NSDictionary?) -> Bool 
    {
        application.registerUserNotificationSettings(UIUserNotificationSettings(forTypes: UIUserNotificationType.Sound|UIUserNotificationType.Alert |UIUserNotificationType.Badge, categories: nil)   

        return true
    }

现在您也可以收到本地通知了。

Answer 3

一旦在给定日期触发本地通知，它就不会在 [UIApplication sharedApplication].scheduledLocalNotifications 数组中显示详细信息。因此，如果您为 fireDate 提供一些间隔计数（从 CurrentDate 到 10~20 秒），它将向您显示详细信息。

Answer 4

我也面临同样的问题，最后我得到了解决它的原因。

如果您没有在通知对象中设置 fireDate 。它的工作很完美，但是当您尝试获取通知列表时，它总是空白。

这里是没有设置触发日期的通知对象

<UIConcreteLocalNotification: 0x7fc1637aedb0>{fire date = (null), time zone = Asia/Kolkata (GMT+5:30) offset 19800, repeat interval = 0, repeat count = UILocalNotificationInfiniteRepeatCount, next fire date = Tuesday, September 5, 2017 at 3:31:44 PM India Standard Time, user info = (null)}

这是带有触发日期的通知对象

<UIConcreteLocalNotification: 0x7f96715d0ff0>{fire date = Tuesday, September 5, 2017 at 3:35:17 PM India Standard Time, time zone = Asia/Kolkata (GMT+5:30) offset 19800, repeat interval = 0, repeat count = UILocalNotificationInfiniteRepeatCount, next fire date = Tuesday, September 5, 2017 at 3:35:17 PM India Standard Time, user info = (null)}

这里是您可以评论开火日期并检查其不同之处的代码

    let localNotification = UILocalNotification()
     **//Comment ..firedate and test it**
    localNotification.fireDate = NSDate(timeIntervalSinceNow: 5)
    localNotification.alertBody = "new Blog Posted at iOScreator.com"
    localNotification.timeZone = NSTimeZone.defaultTimeZone()
    localNotification.applicationIconBadgeNumber = UIApplication.sharedApplication().applicationIconBadgeNumber + 1
     UIApplication.sharedApplication().scheduleLocalNotification(localNotification)

    print(localNotification)

   for notification in   UIApplication.sharedApplication().scheduledLocalNotifications! as [UILocalNotification] {

        print(notification)

    }