【发布时间】:2015-10-04 16:35:36
【问题描述】:
我要将 NSURLConnection 转换为 AFNetworking 2.0。当我使用 NSURLConnection 发布工作正常的数据时。但我不知道如何使用 AFNetworking 2.0 来做到这一点。
这里是 NSURLConnection 请求的代码片段。
#define API_URL @https://myurl.com//login.php"
#define LOGIN_POST_TYPE @"app_data={\"app_data\":{\"user\":\"%@\",\"password\":\"%@\"}}"
+(void) post:(NSString*)api AndPostData:(NSData*)postData AndCallback: (void (^)(id result, NSError *error))callback {
NSString *postLength = [NSString stringWithFormat:@"%lu", (unsigned long)[postData length]];
NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init] ;
[request setURL:[NSURL URLWithString:API_URL];
[request setHTTPMethod:@"POST"];
[request setValue:postLength forHTTPHeaderField:@"Content-Length"];
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
[request setTimeoutInterval:10.0];
[request setHTTPBody:postData];
NSOperationQueue *queue = [[NSOperationQueue alloc] init];
[NSURLConnection sendAsynchronousRequest:request queue:queue completionHandler:^(NSURLResponse *response, NSData *data, NSError *connectionError)
{
NSLog(@"%@",response);
if ([data length] >0 && connectionError == nil)
{
NSString *dataStr = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
callback([dataStr JSONValue], nil);
}
else
{
callback(nil, connectionError);
}
}];
}
+(void) callAPIWithType:(int)apiType withParams:(NSDictionary *)param andCallback:(void(^)(id result, NSError *error)) callback
{
NSString *strPost = [NSString stringWithFormat:LOGIN_POST_TYPE, param[@"email"], param[@"password"]];
NSLog(@"%@", post);
NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];
[self post:API_URL AndPostData:postData AndCallback:^(id result, NSError *error) {
callback(result, error);
}];
}
就像我说的,这段代码运行良好。但是如何将此代码转换为 AFNetworking 2.0? 我用 AFNetworking 做了很多尝试。但是所有的方法都不适合我。 我得到错误响应。
我该怎么做?
【问题讨论】:
标签: ios objective-c json afnetworking nsurlconnection