从 AVFullScreenViewController iOS 8 获取媒体链接

Question

我正在尝试在某些内容开始播放时获取视频链接（例如任何 YouTube 视频）。

首先我捕捉到视频开始播放的时间

[[NSNotificationCenter defaultCenter] addObserver:self selector:@selector(videoStarted:) name:@"UIWindowDidBecomeVisibleNotification" object:nil];

然后延迟尝试获取链接

-(void)videoStarted:(NSNotification *)notification
{
    NSLog(@"notification dic = %@", [notification userInfo]);
    [self performSelector:@selector(detectModal) withObject:nil afterDelay:2.5f];
}

-(void)detectModal
{
    CUViewController *controller = (CUViewController *)[appDelegate.window rootViewController].presentedViewController;
    NSLog(@"Presented modal = %@", [appDelegate.window rootViewController].presentedViewController);
    if(controller && [controller respondsToSelector:@selector(item)])
    {
        id currentItem = [controller item];
        if(currentItem && [currentItem respondsToSelector:@selector(asset)])
        {
            AVURLAsset *asset = (AVURLAsset *)[currentItem asset];
            if([asset respondsToSelector:@selector(URL)] && asset.URL)
                [self newLinkDetected:[[asset URL] absoluteString]];
            NSLog(@"asset find = %@", asset);
        }
    }
    else
    {
        for (UIWindow *window in [UIApplication sharedApplication].windows) {
            if ([window.rootViewController.presentedViewController isKindOfClass:NSClassFromString(@"AVFullScreenViewController")])
            {
                controller = (CUViewController *)window.rootViewController.presentedViewController;
                for(int i = 0; i < [controller.view.subviews count]; i++)
                {
                    UIView *topView = [controller.view.subviews objectAtIndex:i];
                    NSLog(@"top view = %@", topView);
                    for(int j = 0; j < [topView.subviews count]; j++)
                    {
                        UIView *subView = [topView.subviews objectAtIndex:j];
                        NSLog(@"sub view = %@", subView);
                        for (int k = 0; k < [subView.subviews count]; k++)
                        {
                            CUPlayerView *subsubView = (CUPlayerView *)[subView.subviews objectAtIndex:k];
                            NSLog(@"sub sub view = %@ class = %@", subsubView, NSStringFromClass([subsubView class]));
                            if([NSStringFromClass([subsubView class]) isEqualToString:@"AVVideoLayerView"])
                            {
                                NSLog(@"player view controller = %@", subsubView.playerController);
                                CUPlayerController *pController = subsubView.playerController;
                                NSLog(@"item = %@", [pController player]);
                                CUPlayerController *proxyPlayer = pController.playerControllerProxy;
                                if(proxyPlayer)
                                {
                                    AVPlayer *player = [proxyPlayer player];
                                    NSLog(@"find player = %@ chapters = %@", player, proxyPlayer.contentChapters);
                                    break;
                                }
                            }
                        }
                    }
                }
            }
        }
    }
}

CUViewController、CUPlayerView、CUPlayerController - 假的类，看起来像这样

@interface CUPlayerController : UIViewController

@property(nonatomic, retain) id playerControllerProxy;
@property(nonatomic, retain) id player;
@property(nonatomic, retain) id item;

- (id)contentChapters;

@end

在这一行之前一切都很好

NSLog(@"find player = %@ chapters = %@", player, proxyPlayer.contentChapters);

玩家总是零。也许有更简单的方法来获取媒体链接？

Answer 1

首先，我想重点介绍播放 AVPlayerItem 的 AVPlayer。 AVPlayerItem 对象携带对 AVAsset 对象的引用和该资产的表示设置。当您使用 AVPlayer 的 playerWithURL: 方法时，它会自动创建由资产支持的 AVPlayerItem，该资产是名为 AVURLAsset 的 AVAsset 的子类。 AVURLAsset 有一个 URL 属性。因此，如果您使用它，您可以获得当前播放项目的 NSURL。下面是一个获取 URL 的示例函数：

-(NSURL *)urlOfCurrentlyPlayingInPlayer:(AVPlayer *)player{
    // get current asset
    AVAsset *currentPlayerAsset = player.currentItem.asset;
    // make sure the current asset is an AVURLAsset
    if (![currentPlayerAsset isKindOfClass:AVURLAsset.class]) return nil;
    // return the NSURL
    return [(AVURLAsset *)currentPlayerAsset URL];
}

我认为这只是你如何将这个东西适应你的代码的问题。希望这会有所帮助。