以动态/编程方式将 IBAction 分配给按钮

Question

对于我的项目，我创建了一个排序菜单，它以编程方式创建水平滚动的按钮。但是，我正在寻找将 IBAction（特别是写入 Firebase 数据库的操作）动态分配给这些按钮的方法…… 标记按钮和使用条件会起作用吗？

我的代码是

Food.swift - 每个菜单项的属性集

class Food
{
    var title = ""
    var featuredImage: UIImage
    var color: UIColor

    init(title: String, featuredImage: UIImage, color: UIColor)
    {
        self.title = title
        self.featuredImage = featuredImage
        self.color = color
    }

    static func fetchFoods() -> [Food]
    {
        return [
            Food(title: "                   Biscuits", featuredImage: UIImage(named: "f1")!, color: UIColor(red: 63/255.0, green: 71/255.0, blue: 80/255.0, alpha: 0.6)),
            Food(title: "                   Sandwich", featuredImage: UIImage(named: "f2")!, color: UIColor(red: 63/255.0, green: 71/255.0, blue: 80/255.0, alpha: 0.6)),
            Food(title: "             Veg Sandwich", featuredImage: UIImage(named: "f3")!, color: UIColor(red: 63/255.0, green: 71/255.0, blue: 80/255.0, alpha: 0.6)),

        ]
    }
}

UICollectionCell 快速

import UIKit
class FoodCollectionViewCell: UICollectionViewCell {
    @IBOutlet weak var featuredImageView: UIImageView!
    @IBOutlet weak var backgroundColorView: UIView!
    @IBOutlet weak var foodButton: UIButton!
    var food: Food? {
        didSet {
            self.updateUI()
        }
    }
    private func updateUI()
    {
        if let food = food {
            featuredImageView.image = food.featuredImage
            backgroundColorView.backgroundColor = food.color
            foodButton.setTitle("\(food.title)", for: .normal)
        } else {
            featuredImageView.image = nil
            backgroundColorView.backgroundColor = nil
            foodButton.setTitle("", for: .normal)
        }
    }
}

我可以添加到 Food.swift，

 var buttonTag = "" 

然后将标签分配给单个按钮。 在 UICollectionCell.swift 中，附加标签。使用 If...else... 条件将标签与单个 IBAction {ref?.child...")

匹配

谢谢大家！！！

ps.还有另一个用于水平排列菜单项的 swift 文件..

Answer 1

标签是一种方法，但最简单的方法可能是在每个标签上调用addTarget(_:action:for:) 以设置其操作，例如

button.addTarget(button,
                 action: #selector(buttonFunctionThatDoesSomething:),
                 for: .touchUpInside) // or .primaryActionTriggered

第一个参数是要调用其选择器（第二个参数）的对象。 #selector() 语法真的很挑剔；您可能需要阅读 this SO answer 以找出正确的调用方式。

Answer 2

来自苹果文档https://developer.apple.com/library/archive/referencelibrary/GettingStarted/DevelopiOSAppsSwift/ImplementingACustomControl.html。 ：

 button.addTarget(self, action: #selector(funcName), for: .touchUpInside)

然后：

 @objc func funcName()  {
       //do what u want in here
    }