Java RegEx - 正则表达式用开始和结束分割段落

Question

我是 Java 正则表达式的新手。请帮助我。 考虑以下段落，

段落：

            Name abc
            sadghsagh
            hsajdjah Name
            ggggggggg
            !!!
            Name ggg
            dfdfddfdf Name
            !!!
            Name hhhh
            sahdgashdg Name
            asjdhjasdh
            sadasldkalskd
            asdjhakjsdhja
            !!!

我需要将以上段落拆分为以 Name 开头并以 !!! 结尾的文本块.这里我不想用！！！作为分割段落的唯一分隔符。我还需要在我的正则表达式中包含起始序列（名称）。

ie.，我的结果 api 应该看起来像 SplitAsBlocks("Paragraph","startswith Name","endswith ！！！”）

如何实现这一点，请任何人帮助我......

现在我想要与 Brito 相同的输出......但是在这里我在“hsajdjah”之后添加了名称。这里将文本拆分为以下内容：

Name
ggggggggg
!!!

但我需要

Name abc
sadghsagh
hsajdjah Name
ggggggggg
!!!

也就是说，我必须匹配位于行首而不是中间的名称。

请给我建议...

Bart ...请参阅下面的输入案例以了解您的代码...

我需要使用带有参数 start => Name 和 end => 的 API 拆分以下内容！ 但输出各不相同..我只有 3 个块以 Name 开头并以 ! . 我也附上了输出。

String myInput =    "Name hhhhh class0"+ "\n"+
                     "HHHHHHHHHHHHHHHHHH"+ "\n"+
                     "!"+ "\n"+
                     "Name TTTTT TTTT"+ "\n"+
                     "GGGGGG UUUUU IIII"+ "\n"+
                     "!"+ "\n"+
                     "Name JJJJJ WWWW"+ "\n"+
                     "IIIIIIIIIIIIIIIIIIIII"+ "\n"+
                     "!"+ "\n"+
                     "RRRRRRRRRRR TTTTTTTT"+ "\n"+
                     "HHHHHH"+ "\n"+
                     "JJJJJ 1 Name class1"+ "\n"+
                     "LLLLL 5 Name class5"+ "\n"+
                     "!"+ "\n"+
                     "OOOOOO HHHH FFFFFF"+ "\n"+
                     "service 0 Name class12"+ "\n"+
                     "!"+ "\n"+
                     "JJJJJ YYYYYY 3/0"+ "\n"+
                     "KKKKKKK"+ "\n"+
                     "UUU UUU UUUUU"+ "\n"+
                     "QQQQQQQ"+ "\n"+
                         "!";
    String[] tokens = tokenize(myInput, "Name", "!");
    int n = 0;
    for(String t : tokens) {
        System.out.println("---------------------------\n"+(++n)+"\n"+t);
    }

输出：

---------------------------
1
Name hhhhh class0
HHHHHHHHHHHHHHHHHH
!
---------------------------
2
Name TTTTT TTTT
GGGGGG UUUUU IIII
!
---------------------------
3
Name JJJJJ WWWW
IIIIIIIIIIIIIIIIIIIII
!
---------------------------
4
Name class1
LLLLL 5 Name class5
!
---------------------------
5
Name class12
!

在这里我只需要在行首而不是中间的名称... 如何为此添加正则表达式...

Answer 1

试试：

import java.util.*;
import java.util.regex.*;

public class Main { 

    public static String[] tokenize(String text, String start, String end) {
        // old line:
        //Pattern p = Pattern.compile("(?s)"+Pattern.quote(start)+".*?"+Pattern.quote(end));
        // new line:
        Pattern p = Pattern.compile("(?sm)^"+Pattern.quote(start)+".*?"+Pattern.quote(end)+"$");

        Matcher m = p.matcher(text);
        List<String> tokens = new ArrayList<String>();
        while(m.find()) {
            tokens.add(m.group());
        }
        return tokens.toArray(new String[]{});
    }

    public static void main(String[] args) {
        String text = "Name abc" + "\n" +
            "sadghsagh"          + "\n" +
            "hsajdjah Name"      + "\n" +
            "ggggggggg"          + "\n" +
            "!!!"                + "\n" +
            "Name ggg"           + "\n" +
            "dfdfddfdf Name"     + "\n" +
            "!!!"                + "\n" +
            "Name hhhh"          + "\n" +
            "sahdgashdg Name"    + "\n" +
            "asjdhjasdh"         + "\n" +
            "sadasldkalskd"      + "\n" +
            "asdjhakjsdhja"      + "\n" +
            "!!!";
        String[] tokens = tokenize(text, "Name", "!!!");
        int n = 0;
        for(String t : tokens) {
            System.out.println("---------------------------\n"+(++n)+"\n"+t);
        }
    }
}

Answer 2

String s = "Name abc sadghsagh hsajdjah !!! Name ggg dfdfddfdf !!! Name hhhh sahdgashdg asjdhjasdh sadasldkalskd asdjhakjsdhja !!!!! ";
String startsWith = "Name";
String endsWith = "!!!";

// non-greedily get all groups starting with Name and ending with !!!
String pattern = String.format("(%s).*?(%s)", Pattern.quote(startsWith), Pattern.quote(endsWith));
System.out.println(pattern);

Matcher m = Pattern.compile(pattern, Pattern.DOTALL).matcher(s);
while (m.find()) 
  System.out.println(m.group());

输出：

(\QName\E).*?(\Q!!!\E)
Name abc sadghsagh hsajdjah !!!
Name ggg dfdfddfdf !!!
Name hhhh sahdgashdg asjdhjasdh sadasldkalskd asdjhakjsdhja !!!

Answer 3

如果您想在结果中同时保留Name 和!!!，也应该执行以下操作。

String[] 部分 = string.split("(?=(Name|!!!))");

编辑：这是更正的版本：

String[] parts = string.split("(?<=!!!)\\s*(?=Name)");

这将在!!! 和Name 之间的任何空白处拆分，仅此而已；特此保留这两个部分。如果您不想在 !!!Name 上拆分，请将 \\s* 替换为 \\s+ 以允许一对多匹配而不是零对多匹配。

Edit2：附上输入/输出的例子。输入是从 topicstart 复制的：

String string = "Name hhhhh class0" + "\n" + "HHHHHHHHHHHHHHHHHH" + "\n" + "!" + "\n"
    + "Name TTTTT TTTT" + "\n" + "GGGGGG UUUUU IIII" + "\n" + "!" + "\n"
    + "Name JJJJJ WWWW" + "\n" + "IIIIIIIIIIIIIIIIIIIII" + "\n" + "!" + "\n"
    + "RRRRRRRRRRR TTTTTTTT" + "\n" + "HHHHHH" + "\n" + "JJJJJ 1 Name class1" + "\n"
    + "LLLLL 5 Name class5" + "\n" + "!" + "\n" + "OOOOOO HHHH FFFFFF" + "\n"
    + "service 0 Name class12" + "\n" + "!" + "\n" + "JJJJJ YYYYYY 3/0" + "\n" + "KKKKKKK"
    + "\n" + "UUU UUU UUUUU" + "\n" + "QQQQQQQ" + "\n" + "!";

String[] parts = string.split("(?<=!)\\s*(?=Name)");
for (String part : parts) {
    System.out.println(part);
    System.out.println("---------------------------------");
}

输出：

Name hhhhh class0
HHHHHHHHHHHHHHHHHH
!
---------------------------------
Name TTTTT TTTT
GGGGGG UUUUU IIII
!
---------------------------------
Name JJJJJ WWWW
IIIIIIIIIIIIIIIIIIIII
!
RRRRRRRRRRR TTTTTTTT
HHHHHH
JJJJJ 1 Name class1
LLLLL 5 Name class5
!
OOOOOO HHHH FFFFFF
service 0 Name class12
!
JJJJJ YYYYYY 3/0
KKKKKKK
UUU UUU UUUUU
QQQQQQQ
!
---------------------------------

看起来不错？