【发布时间】:2015-04-23 00:22:38
【问题描述】:
我正在处理电话簿,到目前为止,我已经成功地让用户输入他们的信息,将其保存为字符串,将字符串保存到文件中,并使用关键字搜索该字符串。但是,它只对输入的第一个联系人起作用。当输入新联系人时,它会覆盖文件中保存的先前字符串。我怎样才能让它打印到下一行,并开发一个可以搜索的联系人列表。任何帮助深表感谢。这是我的代码:
#include <iostream>
#include <string>
#include <ostream>
#include <fstream>
using namespace std;
struct person
{
string Name;
string Address;
string PhoneNumber;
string Email;
};
int main()
{
ResetUserSelection:
vector<person>ContactList;
int userselection = 0;
cout << "Press 1 to Add Contact" << endl;
cout << "Press 2 to Search for Contact"<<endl;
cout << "What do you want to do? ";
cin >> userselection;
if(userselection == 1)
{
person newPerson;
cout << endl;
cin.ignore();
cout << "What is your Name? " ;
getline(cin,newPerson.Name);
cout << "What is your Address? " ;
getline(cin,newPerson.Address);
cout << "What is your Phone Number? " ;
getline(cin,newPerson.PhoneNumber);
cout << "What is your Email? ";
getline(cin,newPerson.Email);
cout << endl;
string fullContact = "Name: " + newPerson.Name + ", Address: " + newPerson.Address + ", Phone Number: " + newPerson.PhoneNumber + ", Email: " + newPerson.Email + "\n";
cout <<fullContact;
cout << endl;
ofstream myfile;
myfile.open ("contactlist.txt");
myfile << fullContact;
myfile.close();
goto ResetUserSelection;
goto ResetUserSelection;
}
else
{
string search;
ifstream Myfile;
Myfile.open ("contactlist.txt");
cout << "Who do you want to search for?" << endl;
cin >> search;
cout << endl;
ifstream myfile;
myfile.open ("contactlist.txt");
string contact;
while(getline(myfile, contact))
{
if(contact.find(search) != string::npos)
{
cout << search << "'s contact info" << endl << contact << endl << endl;
}
}
myfile.close();
goto ResetUserSelection;
}
}
【问题讨论】:
-
这就是人们讨厌
goto的原因,因为有些人给了它最糟糕的用途,你不能写个循环吗?