c ++在字符串中查找重复的子字符串答案

【问题标题】：c++ find repeated substring within stringc ++在字符串中查找重复的子字符串
【发布时间】：2013-11-20 05:42:39
【问题描述】：

我试图找出子字符串在字符串输入中重复的次数，但由于某种原因，当我调用该函数时，它给了我一个奇怪的数字。我已经在 main 中测试过这个函数，它工作正常，但是当我创建一个独立函数时它不起作用。

提前谢谢你

#include <iostream>
#include <cstring>
#include <string>

using namespace std;

int checkHope(string word1)
    {
    int answer;
    int counter;
    for(int i = 0; word1[i] != '\0'; i++)
    {
        answer = word1.find("h", i);
        if ((word1.find("o", (answer+1)) == i+1) && (word1.find("e", (answer+3)) == i+3)) counter++;
    }
    return counter;
    }

int main()
{
    string word1;

    cout << "Please enter a word to check how many times the word \"hope\" appears. You can also have any letter instead of p.: ";
    getline(cin, word1);
    cout << checkHope(word1);

    return 0;
}

【问题讨论】：

尝试将 counter 初始化为 0。如果你不这样做，它的开始是随机的。
uhuuuu 它有效....多么愚蠢的问题...谢谢@RetiredNinja

标签： c++ string function search

【解决方案1】：

//This will work, 
//Changes initialize counter to 0, add condition to check alphabet 'p' also in if condition


#include <iostream>
#include <cstring>
#include <string>

using namespace std;

int checkHope(string word1)
{
  int answer;
  int counter=0;
  for(int i = 0; word1[i] != '\0'; i++)
  {
    answer = word1.find("h", i);
    if ((word1.find("o", (answer+1)) == i+1)
          &&  (word1.find("p", (answer+2)) == i+2)
          && (word1.find("e", (answer+3)) == i+3))
           counter++;
  }
  return counter;
}

int main()
{
  string word1;

  cout << "Please enter a word to check how many times the word \"hope\" appears. You can also have any letter instead of p.: ";
  getline(cin, word1);
  cout << checkHope(word1);

  return 0;
}

【讨论】：