如何同步线程以捕获相同数量的帧？答案

【问题标题】：How to synchronize threads to capture same number of frames?如何同步线程以捕获相同数量的帧？
【发布时间】：2012-12-09 02:58:30
【问题描述】：

我正在开发 Kinect 应用程序。我有两个线程，一个用于读取关节的值（包含 20 个关节的 x、y、z 坐标），另一个用于读取深度值（每帧 76800 个短值）。我从按下开始按钮开始记录这些值，直到按下结束按钮。我希望编写相同数量的关节和深度帧，但我总是以很多关节帧结束。我捕获了 150 个深度帧但 180 个关节帧，我认为这是因为深度写入缓冲区的数据量。联合只在每帧中写入 60 个浮点数，但深度为 76800 短裤。

如何从每个捕获相同数量的帧？（Kinect 捕捉深度和坐标 25 到 30 FPS）

此日志还显示了每个调用的线程数不相等：

112/11/9 4:19:58: SKELETON

112/11/9 4:19:58: DEPTH

112/11/9 4:19:58: SKELETON

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112/11/9 4:19:59: DEPTH

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112/11/9 4:19:59: SKELETON

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112/11/9 4:19:59: SKELETON

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112/11/9 4:20:8: DEPTH

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112/11/9 4:20:9: DEPTH

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112/11/9 4:20:9: SKELETON

112/11/9 4:20:9: SKELETON

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112/11/9 4:20:10: DEPTH

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112/11/9 4:20:10: DEPTH

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112/11/9 4:20:10: DEPTH

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【问题讨论】：

您使用什么事件来捕获数据？ AllFramesReady 与个别事件相比，可以帮助您同步数字。还可以查看 CodePlex 的“Kinect Toolbox”项目；提供录音机。
谢谢，但我正在 c++ 下开发，AllFramesReady 在 c++ 中不能作为事件使用

标签： c++ multithreading synchronization kinect

【解决方案1】：

拥有一个由锁和条件变量保护的共享表，该变量保持对已捕获的每种类型的帧数的计数。如果任一线程发现它捕获的帧比另一个多，则让它阻塞条件变量。当任一线程完成获取帧时，它会增加其类型的计数并广播条件变量。

【讨论】：