C++ 从文本文件读取到数组/字符串

Question

这是我目前的代码。

我需要做的是从两个不同的文本文件中读取，矩阵 A 和矩阵 B。

我可以这样做，但是对于我读取的每个文本文件矩阵，它只提供了

1 0 0 

（所以基本上是第一行）Matrix A 的整个文本文件实际上是

1 0 0
2 0 0
3 0 0

那么有人知道我该怎么做吗？

谢谢！

#include <iostream>  //declaring variables
#include <iomanip>
#include <string>
#include <fstream>

using namespace std;
string code(string& line);
int main()
{
    ofstream outf;
    ifstream myfile;
    string infile;
    string line;
    string outfile;

    cout << "Please enter an input file (A.txt) for Matrix A or (B.txt) for Matrix B" << endl;
    cin >> infile;   //prompts user for input file

    if (infile == "A.txt")
    {      //read whats in it and write to screen
        myfile.open("A.txt");
        cout << endl;
        getline (myfile, line);
        cout << line << endl;

    }
    else
        if (infile == "B.txt")
        {
            myfile.open("B.txt");
            cout << endl;
            getline (myfile, line);
            cout << line << endl;
        }
        else
    { 
        cout << "Unable to open file." << endl;
    }
        //{
            //while("Choose next operation");
        //}
    return 0;
}

Answer 1

嗯，getline 显然得到了一行。

您应该逐行阅读，直到文件末尾，您可以通过以下方式实现：

while (getline(myfile, line))
    out << line << endl;

这意味着：当从 myfile 中获取一行时，将该行写入输出流。

Answer 2

您只阅读一次，所以这不是奇迹。您将需要使用 while 或 for 循环进行连续阅读。你会这样写：

while (getline (myfile, line))
    cout << line << endl;

这就是要编写的全部代码：

#include <iostream>  //declaring variables
#include <iomanip>
#include <string>
#include <fstream>

using namespace std;
string code(string& line);
int main()
{
    ofstream outf;
    ifstream myfile;
    string infile;
    string line;
    string outfile;

    cout << "Please enter an input file (A.txt) for Matrix A or (B.txt) for Matrix B" << endl;
    cin >> infile;   //prompts user for input file

    if (infile == "A.txt")
    {      //read whats in it and write to screen
        myfile.open("A.txt");
        cout << endl;
        while (getline (myfile, line))
            cout << line << endl;


    }
    else
        if (infile == "B.txt")
        {
            myfile.open("B.txt");
            cout << endl;
            while (getline (myfile, line))
                cout << line << endl;
        }
        else
    { 
        cout << "Unable to open file." << endl;
    }
        //{
            //while("Choose next operation");
        //}
    return 0;
}

Answer 3

使用getline 是最简单的方法：

#include <string>
#include <iostream>
#include <fstream>
using namespace std;

void read_file_line_by_line(){
    ifstream file;
    string line;
    file.open("path_to_file");
    while (getline (file, line))
        cout << line << endl;
}

int main(){
    read_file_line_by_line();
    return 0;
}