【发布时间】:2015-06-11 17:17:34
【问题描述】:
您好,我是 JSP 新手,我使用 Jersey 库 1.19 包创建 JSON Web 服务。此 Web 服务在 Android 和 iOS 中运行良好,但通过 Ajax 调用时,它显示类似跨域错误的错误。
Web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
id="WebApp_ID" version="2.5">
<display-name>Sales Report</display-name>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>ServletAdaptor</servlet-name>
<servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>com.sun.jersey.config.property.packages</param-name>
<param-value>model</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>ServletAdaptor</servlet-name>
<url-pattern>/report/*</url-pattern>
</servlet-mapping>
</web-app>
网络服务类
@GET
@Path("/sales_order_details")
@Produces("application/json")
public String order_details(){
String feeds = null;
try
{
ArrayList<Order_headers> whole_data = null;
Project projectManager= new Project();
whole_data = projectManager.order_details();
feeds=Arraylist_to_json.Order_edtails(whole_data);
} catch (Exception e){
e.printStackTrace();
}
return feeds;
}
在 Google 中搜索后,我得到了一种添加 ContainerResponseFilter 的解决方案,但现在也遇到了同样的错误。
CrossDomainFilter 类
public class CrossDomainFilter implements ContainerResponseFilter {
@Override
public ContainerResponse filter(ContainerRequest req,ContainerResponse contResp) {
// TODO Auto-generated method stub
ResponseBuilder resp = Response.fromResponse(contResp.getResponse());
resp.header("Access-Control-Allow-Origin", "*").header("Access-Control-Allow-Methods", "GET, POST, OPTIONS");
String reqHead = req.getHeaderValue("Access-Control-Request-Headers");
if (null != reqHead && !reqHead.equals("")) {
resp.header("Access-Control-Allow-Headers", reqHead);
}
contResp.setResponse(resp.build());
return contResp;
}
}
在web.xml 中添加了另一个<init-param>
<init-param>
<param-name>com.sun.jersey.spi.container.ContainerResponseFilters</param-name>
<param-value>cros.filter.CrossDomainFilter</param-value>
</init-param>
Ajax 调用
$(function() {
$.ajax({
type:'GET',
dataType:'jsonp',
jsonp:'jsonp',
url:'http://192.168.1.2:8080/Sales_report/report/customer_details',
success:function(data) {
$.each(data["customer_details"], function(index, item) {
var $tag = item.city;
var $count = item.customer_id;
$("body").append('<div class="stackoverflow"> The Tag <span class="q-tag">' + $tag + '</span> has <span class="q-count">' + $count + '</span> Questions.</div>')
});
},
error:function() {
alert("Sorry, I can't get the feed");
}
});
});
谁能知道帮我解决这个问题。
【问题讨论】:
-
如果您使用的是 GoogleChrome,您可以使用
--disable-web-security标志打开它。 -
@bigdestroyer 我想念 CrossDomainFilter 类中的
@Provider。感谢您提供的信息。