【发布时间】:2017-10-10 07:10:53
【问题描述】:
以这个yaml节点为例:
- flow:
- do:
? command:
- command1: command
- command2: command
- command3: command
name: nameblock
descr: descrblock
: block_1
对于值“block_1”,键是地图节点。怎么用yaml-cpp删除最里面的值“block_1”,让整个节点变成:
- flow:
- do:
command:
- command1: command
- command2: command
- command3: command
name: nameblock
descr: descrblock
有什么建议吗?赞赏!
【问题讨论】: