【发布时间】:2017-01-03 12:00:14
【问题描述】:
我正在尝试使用链表在 java 中创建优先级队列,但有些东西不起作用。我了解优先级队列的一般功能,但在 java 方面我是一个完整的初学者。我查看了其他示例,但似乎找不到我的问题所在。有什么建议吗?我注意到的一件事是使用类型或其他什么,但我不确定那是什么。
头等舱:
public class Node { //Node class structure
int data; //data contained in Node
Node next; //pointer to Next Node
public int getData() {
return data;
}
public void setData(int data) {
this.data = data;
}
public Node getNext() {
return next;
}
public void setNext(Node next) {
this.next = next;
}
}
二等:
import work.Node;
//basic set-up of a singly linked list
public class SLList{
Node head; //head of SLList
Node tail; //tail of SLList
int n; //number of elements in SLList
}
第三类:
import work.Node;
public class PriorityQueue extends SLList{
//add a new node
public void add(int x){
Node y = new Node();
y.data = x;
if (tail == null){ //if there is no existing tail, thus an empty list
tail = y; //assign tail and head as new node y
head = y;
}
else if (y.data < head.data){ //if new node y is the smallest element, thus highest priority
y.next = head; //assign y's next to be current head of queue
head = y; //reassign head to be actual new head of queue (y)
}
else{ //if there is already a tail node
tail.next = y; //assign the tail's pointer to the new node
tail = y; //reassign tail to actual new tail of queue (y)
}
n++; //increment the queue's size
}
//delete the minimim (highest priority value) from the queue
public Node deleteMin(){
if (n == 0){ //if the list is of size 0, and thus empty
return null; //do nothing
}
else{ //if there are node(s) in the list
Node min = head; //assign min to the head
head = head.next; //reassign head as next node,
n--; //decrement list size
return min; //return the minimum/highest priority value
}
}
//return the size of the queue
public int size() {
return n;
}
}
测试代码:
import work.Node;
import work.SLList;
import work.PriorityQueue;
public class Test {
public static void main(String[] args){
PriorityQueue PQueue1 = new PriorityQueue();
PQueue1.add(3);
PQueue1.add(2);
PQueue1.add(8);
PQueue1.add(4);
System.out.println("Test add(x): " + PQueue1);
System.out.println("Test size() " + PQueue1.size());
PriorityQueue PQueue2 = new PriorityQueue();
PQueue2 = PQueue1.deleteMin(); //the data types don't line up but I don't know what should be changed
System.out.println("Test deleteMin() " + PQueue2);
System.out.println("Test size() " + PQueue2.size());
}
}
【问题讨论】:
-
您想将 PriorityQueue 类型的引用分配给 Node 类型的值,它们不会在一个类层次结构中发生事件。
-
“某事不工作”请明确。什么不工作?
-
不要评论所有内容。
Node head- 是的,它是列表的首位。你不必用英文写。注释的目的不是将代码翻译成英文。您应该使用 cmets 来解释您所写内容背后的原因。不要将 size 变量声明为int n并在其旁边写注释,而是这样做:int size。它更加干净和明显。通过解释为什么会发生而不是发生什么来发表评论:)
标签: java linked-list nodes priority-queue