HTTP 状态 405 – Apache Tomcat 服务器中不允许的方法 [重复]答案

【问题标题】：HTTP Status 405 – Method Not Allowed in Apache Tomcat Server [duplicate]HTTP 状态 405 – Apache Tomcat 服务器中不允许的方法 [重复]
【发布时间】：2021-06-20 06:29:50
【问题描述】：

我在我的 Java 后端遇到 HTTP 状态 405 – Method Not Allowed 错误。我正在使用 Apache Tomcat 服务器输入状态报告

此 URL 不支持消息 HTTP 方法 GET

描述在请求行中接收到的方法是源服务器已知的，但目标资源不支持。

截图如下：

我的 Web.xml 文件：

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
 xmlns="http://xmlns.jcp.org/xml/ns/javaee" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee    
 http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd" id="WebApp_ID" version="3.1">
<display-name>Backend</display-name>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
<welcome-file>index.htm</welcome-file>
<welcome-file>index.jsp</welcome-file>
<welcome-file>default.html</welcome-file>
<welcome-file>default.htm</welcome-file>
<welcome-file>default.jsp</welcome-file>
</welcome-file-list>
<filter>
<filter-name>CorsFilter</filter-name>
<filter-class>org.apache.catalina.filters.CorsFilter</filter-class>
<init-param>
  <param-name>cors.allowed.origins</param-name>
  <param-value>http://localhost:3000</param-value>
</init-param>
</filter>
<filter-mapping>
<filter-name>CorsFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<servlet>
<servlet-name>BatchDisplay</servlet-name>
<servlet-class>com.hello.BatchDisplay</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>BatchDisplay</servlet-name>
<url-pattern>/BatchDisplay.do</url-pattern>
</servlet-mapping>
<servlet>
<servlet-name>AddServlet</servlet-name>
<servlet-class>com.hello.AddServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>AddServlet</servlet-name>
<url-pattern>/AddServlet.do</url-pattern>
</servlet-mapping>
</web-app>

当我从 Postman 执行 Post 请求时，我收到了这个错误。

我的 Java 后端代码：

    package com.hello;
    import java.io.*;  
    import java.sql.*;  
    import javax.servlet.ServletException;
    import javax.servlet.http.*;

public class AddServelet extends HttpServlet { 

private static final long serialVersionUID = 1L;
protected void doPost(HttpServletRequest request,HttpServletRequest response) throws ServletException
{
    
    try {
        
        String custNumber=request.getParameter("cust_number");
        String nameCustomer=request.getParameter("name_customer");
        String invoiceID=request.getParameter("invoice_id");
        Double TotalOpenAmount=Double.parseDouble(request.getParameter("total_open_amount"));
        String dueinDATE=request.getParameter("due_in_date");
        String Notes=request.getParameter("notes");
        System.out.print("Acquiring Connection");
        Connection connection = DriverManager.getConnection("com.mysql.jdbc.Driver", "root", "abcd");
        System.out.print("Connected Successfully");
        String sql="INSERT INTO invoice 
        invoice_details(cust_number,name_customer,invoice_id,total_open_amount,due_in_date,notes) 
        VALUES (?,?,?,?,?,?)";
        PreparedStatement statement = connection.prepareStatement(sql);
        statement.setString(1, nameCustomer);  
        statement.setString(2, custNumber);  
        statement.setString(3, invoiceID);  
        statement.setDouble(4, TotalOpenAmount);  
        statement.setString(5, dueinDATE);
        statement.setString(6, Notes);                 
        statement.executeUpdate();  
        
        
    }
    catch(SQLException e){
        e.printStackTrace();
    }
    finally
    {
        
    }
}
}

我真的不知道为什么会出现这样的错误。请建议我一种调试方法。

【问题讨论】：

您是否打算覆盖 doGet 而不是 doPost？
错误消息“此 URL 不支持消息 HTTP 方法 GET”表示使用了 GET，但问题的其他地方是“当我执行来自 Postman 的 Post 请求时，我收到此错误。”这表明您正在发送 POST 请求。

标签： servlets http-status-code-405

【解决方案1】：

如果你想通过 GET 方法调用，你需要重写 doGet 方法；

    @Override
    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        try {
        
        String custNumber=request.getParameter("cust_number");
        String nameCustomer=request.getParameter("name_customer");
        String invoiceID=request.getParameter("invoice_id");
        Double TotalOpenAmount=Double.parseDouble(request.getParameter("total_open_amount"));
        String dueinDATE=request.getParameter("due_in_date");
        String Notes=request.getParameter("notes");
        System.out.print("Acquiring Connection");
        Connection connection = DriverManager.getConnection("com.mysql.jdbc.Driver", "root", "abcd");
        System.out.print("Connected Successfully");
        String sql="INSERT INTO invoice 
        invoice_details(cust_number,name_customer,invoice_id,total_open_amount,due_in_date,notes) 
        VALUES (?,?,?,?,?,?)";
        PreparedStatement statement = connection.prepareStatement(sql);
        statement.setString(1, nameCustomer);  
        statement.setString(2, custNumber);  
        statement.setString(3, invoiceID);  
        statement.setDouble(4, TotalOpenAmount);  
        statement.setString(5, dueinDATE);
        statement.setString(6, Notes);                 
        statement.executeUpdate();  
        
        
    }
    catch(SQLException e){
        e.printStackTrace();
    }
    finally
    {
        
    }

    }

当你需要使用 GET 方法时：覆盖 doGet(HttpServletRequest request, HttpServletResponse response), POST-doPost(HttpServletRequest request, HttpServletResponse response), both - doGet 和 doPost

【讨论】：