【发布时间】：2012-02-01 12:35:47
【问题描述】：
我正在使用 Windows 服务中的 CreateProcessAsUser（请我们保持主题并假设我有充分的理由这样做）。与其他人在这里问的相反，我在我的活动终端会话（会话 1）中得到了一个窗口，而不是与服务相同的会话（会话 0）——这是不可取的。
我挪用了Scott Allen's code；并想出了以下内容。显着的变化是“revert to self”、“CREATE_NO_WINDOW”和命令行参数支持。
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Security;
using System.Runtime.InteropServices;
using System.Diagnostics;
using System.Security.Principal;
using System.ComponentModel;
using System.IO;
namespace SourceCode.Runtime.ChildProcessService
{
[SuppressUnmanagedCodeSecurity]
class NativeMethods
{
[StructLayout(LayoutKind.Sequential)]
public struct STARTUPINFO
{
public Int32 cb;
public string lpReserved;
public string lpDesktop;
public string lpTitle;
public Int32 dwX;
public Int32 dwY;
public Int32 dwXSize;
public Int32 dwXCountChars;
public Int32 dwYCountChars;
public Int32 dwFillAttribute;
public Int32 dwFlags;
public Int16 wShowWindow;
public Int16 cbReserved2;
public IntPtr lpReserved2;
public IntPtr hStdInput;
public IntPtr hStdOutput;
public IntPtr hStdError;
}
[StructLayout(LayoutKind.Sequential)]
public struct PROCESS_INFORMATION
{
public IntPtr hProcess;
public IntPtr hThread;
public Int32 dwProcessID;
public Int32 dwThreadID;
}
[StructLayout(LayoutKind.Sequential)]
public struct SECURITY_ATTRIBUTES
{
public Int32 Length;
public IntPtr lpSecurityDescriptor;
public bool bInheritHandle;
}
public enum SECURITY_IMPERSONATION_LEVEL
{
SecurityAnonymous,
SecurityIdentification,
SecurityImpersonation,
SecurityDelegation
}
public enum TOKEN_TYPE
{
TokenPrimary = 1,
TokenImpersonation
}
public const int GENERIC_ALL_ACCESS = 0x10000000;
public const int CREATE_NO_WINDOW = 0x08000000;
[
DllImport("kernel32.dll",
EntryPoint = "CloseHandle", SetLastError = true,
CharSet = CharSet.Auto, CallingConvention = CallingConvention.StdCall)
]
public static extern bool CloseHandle(IntPtr handle);
[
DllImport("advapi32.dll",
EntryPoint = "CreateProcessAsUser", SetLastError = true,
CharSet = CharSet.Ansi, CallingConvention = CallingConvention.StdCall)
]
public static extern bool
CreateProcessAsUser(IntPtr hToken, string lpApplicationName, string lpCommandLine,
ref SECURITY_ATTRIBUTES lpProcessAttributes, ref SECURITY_ATTRIBUTES lpThreadAttributes,
bool bInheritHandle, Int32 dwCreationFlags, IntPtr lpEnvrionment,
string lpCurrentDirectory, ref STARTUPINFO lpStartupInfo,
ref PROCESS_INFORMATION lpProcessInformation);
[
DllImport("advapi32.dll",
EntryPoint = "DuplicateTokenEx")
]
public static extern bool
DuplicateTokenEx(IntPtr hExistingToken, Int32 dwDesiredAccess,
ref SECURITY_ATTRIBUTES lpThreadAttributes,
Int32 ImpersonationLevel, Int32 dwTokenType,
ref IntPtr phNewToken);
public static Process CreateProcessAsUser(string filename, string args)
{
var hToken = WindowsIdentity.GetCurrent().Token;
var hDupedToken = IntPtr.Zero;
var pi = new PROCESS_INFORMATION();
var sa = new SECURITY_ATTRIBUTES();
sa.Length = Marshal.SizeOf(sa);
try
{
if (!DuplicateTokenEx(
hToken,
GENERIC_ALL_ACCESS,
ref sa,
(int)SECURITY_IMPERSONATION_LEVEL.SecurityIdentification,
(int)TOKEN_TYPE.TokenPrimary,
ref hDupedToken
))
throw new Win32Exception(Marshal.GetLastWin32Error());
var si = new STARTUPINFO();
si.cb = Marshal.SizeOf(si);
si.lpDesktop = "";
var path = Path.GetFullPath(filename);
var dir = Path.GetDirectoryName(path);
// Revert to self to create the entire process; not doing this might
// require that the currently impersonated user has "Replace a process
// level token" rights - we only want our service account to need
// that right.
using (var ctx = WindowsIdentity.Impersonate(IntPtr.Zero))
{
if (!CreateProcessAsUser(
hDupedToken,
path,
string.Format("\"{0}\" {1}", filename.Replace("\"", "\"\""), args),
ref sa, ref sa,
false, 0, IntPtr.Zero,
dir, ref si, ref pi
))
throw new Win32Exception(Marshal.GetLastWin32Error());
}
return Process.GetProcessById(pi.dwProcessID);
}
finally
{
if (pi.hProcess != IntPtr.Zero)
CloseHandle(pi.hProcess);
if (pi.hThread != IntPtr.Zero)
CloseHandle(pi.hThread);
if (hDupedToken != IntPtr.Zero)
CloseHandle(hDupedToken);
}
}
}
}
现在假设该服务在“Domain\MyService”下运行，并且我当前以“Domain\Administrator”身份登录 - 我正在将控制台应用程序作为工作进程启动。当我使用客户端应用程序访问服务（服务未以控制台模式启动，即它处于会话 0 中）并执行调用 CreateProcessAsUser 的方法时，工作进程出现在我的桌面上。
现在我可以让它成为一个没有窗口的 Windows 应用程序来回避控制台窗口的创建；但是，归根结底，它仍在会话 1 中创建。
知道为什么控制台应用程序没有在与服务相同的会话中创建吗？
【问题讨论】：
-
它看起来可能与this dark magic 有关，但我不知道如何跳过它。
-
尝试使用“Service-0×0-3e7$\Default”作为桌面 - 这会导致应用程序崩溃。
-
什么版本的 Windows？您是否尝试过将 lpDeskTop 设为 null？
-
@HansPassant Server 2008 R2。我确实尝试将
lpDeskTop设置为null（这会导致工作进程崩溃） - 我还尝试将其设置为各种硬编码值，例如内置会话 0 桌面名称。 -
如果有这么多情况导致崩溃，则可能存在编组问题。你能发布你的结构和外部的代码吗？
标签： c# windows-services pinvoke