【问题标题】:How to pause the animation on mouse hover on image如何在鼠标悬停在图像上时暂停动画
【发布时间】:2018-05-18 22:13:46
【问题描述】:

我需要帮助来停止鼠标悬停动画并继续鼠标悬停。请参阅下面的 url 以查看代码。谢谢

http://jsfiddle.net/AbdiasSoftware/F8x4p/

        $(window).load(function(){
        var pos = $('#center').position(),
        radiusSat = $('#sat1').width() * 0.5,
        radius = $('#center').width() * 0.5,
        cx = pos.left + radius,
        cy = pos.top + radius,
        x, y, angle = 0, 
        angles = [],
        spc = 360 / 25,
        deg2rad = Math.PI / 180,
        i = 0;

    for(;i < 25; i++) {
        angles.push(angle);
        angle += spc;
    }

    /// space out radius
    radius += (radiusSat + 25);

    loop();

    function loop() {
    for(var i = 0; i < angles.length; i++) {

        angle = angles[i];

        x = cx + radius * Math.cos(angle * deg2rad);
        y = cy + radius * Math.sin(angle * deg2rad);

        $('#sat' + i).css({left:x - radiusSat, top:y - radiusSat});


    angles[i] += 0.1;
        if (angles[i] > 360) angles[i] = 0;
    }

    requestAnimationFrame(loop);

}
});

【问题讨论】:

标签: javascript jquery


【解决方案1】:

试试这个-

var pos = $('#center').position(),
    radiusSat = $('#sat1').width() * 0.5,
    radius = $('#center').width() * 0.5,
    cx = pos.left + radius,
    cy = pos.top + radius,
    x, y, angle = 0, angles = [],
    spc = 360 / 5,
    deg2rad = Math.PI / 180,
    i = 0;

for(;i < 5; i++) {
    angles.push(angle);
    angle += spc;
}
stop();
/// space out radius
radius += (radiusSat + 10);
$("#center").mouseover(function(){
   start();
});
$("#center").mouseout(function(){
   stop();
});

var requestId;

function loop(time) {
    requestId = undefined;

   for(var i = 0; i < angles.length; i++) {

        angle = angles[i];
        
        x = cx + radius * Math.cos(angle * deg2rad);
        y = cy + radius * Math.sin(angle * deg2rad);

        $('#sat' + i).css({left:x - radiusSat, top:y - radiusSat});
    
        angles[i] = angles[i] + 1;
        if (angles[i] > 360) angles[i] = 0;
    }
    
    //requestAnimationFrame(loop);

    stop();
}

function stop() {
    if (!requestId) {
       requestId = window.requestAnimationFrame(loop);
    }
}

function start() {
    if (requestId) {
       window.cancelAnimationFrame(requestId);
       requestId = undefined;
    }
}
div {
    border-radius:50%;
    border:2px solid #000;
    position:fixed;
}
#center {
    width:200px;
    height:200px;
    left:100px;
    top:100px;
    
}
#sat0, #sat1, #sat2, #sat3, #sat4 {
    width:50px;
    height:50px;
    
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
<div id="center"></div>
<div id="sat0"></div>
<div id="sat1"></div>
<div id="sat2"></div>
<div id="sat3"></div>
<div id="sat4"></div>

【讨论】:

    【解决方案2】:

    您可以创建一个变量来跟踪鼠标是否在里面,并使用事件来更改变量。

    首先,将您的标记包装在一个包含的 div 中,以便可以轻松地将事件侦听器应用于所有元素:

    <div class="container">
      <div id="center"></div>
      <div id="sat0"></div>
      <div id="sat1"></div>
      <div id="sat2"></div>
      <div id="sat3"></div>
      <div id="sat4"></div>
    </div>
    

    然后添加一个名为mouseEntered 的新变量,并将其设置为false

    然后创建两个事件监听器——一个在鼠标进入容器时将mouseEntered变量设置为true,一个在鼠标离开时将其设置为false

    document.querySelector('.container').addEventListener('mouseenter', function() {
        mouseEntered = true
    })
    document.querySelector('.container').addEventListener('mouseleave', function() {
        mouseEntered = false
    })
    

    最后,将除requestAnimationFrame 之外的所有内容都包装在loop 函数中,并在if 语句中检查mouseEntered 是否为false

    function loop() {
        if (mouseEntered === false) {
          for(var i = 0; i < angles.length; i++) {
    
              angle = angles[i];
    
              x = cx + radius * Math.cos(angle * deg2rad);
              y = cy + radius * Math.sin(angle * deg2rad);
    
              $('#sat' + i).css({left:x - radiusSat, top:y - radiusSat});
    
              angles[i] = angles[i] + 1;
              if (angles[i] > 360) angles[i] = 0;
          }
        }
    
        requestAnimationFrame(loop);
    }
    

    修改更改:http://jsfiddle.net/pbobbr5h/

    【讨论】:

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