【发布时间】:2018-03-08 01:25:03
【问题描述】:
当我在其中一个 lineedit 中插入一个数字时,我想让一个按钮可见。 button 和 linedit 在同一行。我知道 lineedit 的位置或名称,但我不知道如何链接回按钮以使其可见或能够更改颜色。
如果您查看 eventFilter,这就是我卡住的地方,我需要一些帮助。 谢谢
#include "mainwindow.h"
#include "ui_mainwindow.h"
#include <QLineEdit>
#include <QPushButton>
#include <QGridLayout>
#include <QLabel>
#include <QRegion>
#include <QLayoutItem>
#include <QList>
#include<QObject>
#include <QEvent>
#include <QKeyEvent>
#include <QModelIndexList>
#include <QKeySequence>
#include <QSignalMapper>
#include<QIntValidator>
#include <QDebug>
MainWindow::MainWindow(QWidget *parent) :
QMainWindow(parent),
ui(new Ui::MainWindow)
{
ui->setupUi(this);
ui->scrollArea->setVerticalScrollBarPolicy( Qt::ScrollBarAlwaysOn );
ui->scrollArea->setWidgetResizable( true );
QWidget *widget = new QWidget(this);
ui->scrollArea->setWidget( widget );
QGridLayout *gridLayout = new QGridLayout();
widget->setLayout( gridLayout );
QPushButton *button[20];
for (int i = 0; i < 20; i++)
{
QLabel *label = new QLabel( QString( "%1" ).arg( i ) );
gridLayout->addWidget(label,i,1,1,1 );
gridLayout->setColumnMinimumWidth(1, 100);
gridLayout->setColumnMinimumWidth(2, 10);
if (i==5)
{
QLineEdit *lineEdit = new QLineEdit;
gridLayout->addWidget(lineEdit,i,5,1,1);
} else
{
QLineEdit *lineEdit = new QLineEdit(this);
gridLayout->addWidget(lineEdit,i,3,1,1);
lineEdit->setValidator(new QIntValidator(0,100,this));
lineEdit->setObjectName(QString::number(i));
lineEdit->installEventFilter(this);
gridLayout->setColumnMinimumWidth(4, 25);
gridLayout->setColumnMinimumWidth(5, 50);
gridLayout->setColumnMinimumWidth(6, 25);
QLineEdit *lineEdit_B = new QLineEdit;
gridLayout->addWidget(lineEdit_B,i,7,1,1);
lineEdit_B->setValidator(new QIntValidator(0,100,this));
gridLayout->setColumnMinimumWidth(8, 10);
}
gridLayout->setColumnMinimumWidth(9, 10);
button[i] = new QPushButton();
gridLayout->addWidget(button[i],i,10,1,1);
gridLayout->setColumnStretch(10,20);
button[i]->setFixedHeight(20);
button[i]->setFixedWidth(20);
button[i]->setStyleSheet("background-color:red;");
button[i]->setText(QString::number(i));
QRegion* region = new QRegion(*(new QRect(button[i]->x(),button[i]->y(),15,15)),QRegion::Ellipse);
button[i]->setMask(*region);
button[i]->setVisible(false);
gridLayout->setColumnMinimumWidth(10, 50);
gridLayout->setColumnMinimumWidth(11, 10);
}
}
MainWindow::~MainWindow()
{
delete ui;
}
bool MainWindow::eventFilter(QObject * obj, QEvent *event)// *event)
{
if (event->type() == QEvent::KeyPress)
{
ui->lineEdit->setText(QString("%1").arg(obj->objectName()));
QKeyEvent *keyEvent = static_cast<QKeyEvent *>(event);
qDebug() << "key " << keyEvent->key() << "from" << obj;
// HERE'S WHERE I NEED HELP
QPushButton* button = ui->scrollArea->findChild<QPushButton*>();
// I think here I would use a for loop to match the listedit
// with a number with the corresponding push button.
// When i find the push button I set it to yellow.
}
return QObject::eventFilter(obj, event);
}
void MainWindow::on_pushButton_clicked()
{
}
【问题讨论】:
-
首先获取一个指向布局的指针,然后将其转换为QGridLayout。然后知道 LineEdit 的位置,使用 QGridLayout::itemAtPosition 与相同的 row 和 column + 1。最后,使用QLayoutItem::widget 获取指向相邻按钮的指针。
标签: c++ qt qt5 qpushbutton qlineedit