如果输入不正确，有没有办法阻止程序运行？ Python

Question

我一直在尝试编写这段代码，如果某个输入不正确，我需要一种停止代码的方法，这是我目前所拥有的：

first_name = input('PLEASE ENTER YOUR FIRST NAME: ')
last_name = input('PLEASE ENTER YOUR SURNAME: ')
print(f'Hello {first_name} {last_name}, before you enter.')

def age_det():
    age = input(f'How old are you?')
    converted_age = [int(age)]
  
    for num in converted_age: 
      while num>=18:
        print(f'Awesome, {first_name}, welcome to Blablabla')
        num += 100
      while num <= 18:
        break
      print(f'Sorry, {first_name}, but we require you to be at least 18 to enter Blablabla.')
      num += 100

age_det()
#I want the code to stop here if the age entered is under 18    

username = input('Before we start, please pick a username: ')

print(f'Woah! {username}, good choice!')

Answer 1

导入 sys 对象并使用 if 语句检查年龄是否有效。如果不打电话给sys.exit()。

import sys

age = 17
if age < 18:
    sys.exit()

print("Still going") # Doesn't get printed

如果年龄至少为 18 岁：

import sys

age = 25
if age < 18:
    sys.exit()

print("Still going") # Gets printed

Answer 2

首先导入这些：-

import sys

然后在“对不起，我们不允许 18 岁以下”行之后添加这个

input('Press Enter to Continue...')
sys.exit()

另外使用if 而不是while

您的代码可以简化为：-

import sys

first_name=input('PLEASE ENTER YOUR FIRST NAME: ')
last_name=input('PLEASE ENTER YOUR SURNAME: ')
print(f'Hello {first_name} {last_name}, before you enter.')

def age_det():
    age = int(input(f'How old are you?'))
    if num>=18:
        print(f'Awesome, {first_name}, welcome to Blablabla')
    else :
        print(f'Sorry, {first_name}, but we require you to be at least 18 to enter Blablabla.')
        input('Press Enter to Continue...')
        sys.exit()

age_det()