带有 case switch 和 enum 的工作日

Question

我正在尝试在 C 中创建一个带有大小写切换和枚举的程序。我想插入一个在我的枚举日中预设的工作日。 程序运行良好，但输入工作日时出现错误。 代码如下：

#include <stdio.h>

int main(){

    enum days{Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday};
    enum days weekDay;
    int i = 0;

    printf("Insert a week day: ");
    scanf("%s", weekDay);

    switch(weekDay){

    case Sunday:
        i=i+1;
        printf("Number of the day: %i", i);
        break;

    case Monday:
        i=i+2;
        printf("Number of the day: %i", i);
        break;

    (...)

    case Saturday:
        i=i+7;
        printf("Number of the day: %i", i);
        break;

    default:
        printf("Error. Please insert a valid week day.");
        break;

    }

我怎样才能正确地写这个？

Answer 1

scanf 与 %s 说明符扫描字符串，而不是 enums。确保您了解您正在使用的所有数据类型！

不幸的是，C 并不真正关心您分配给enum 成员的实际名称：它们仅供您作为程序员使用，程序本身无法访问它们。试试这样的。

const char* names[] = {"Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday", NULL}; // The name of each day, in order

char buffer[16]; // A place to put the input
scanf("%15s", buffer); // Now `buffer` contains the string the user typed, to a maximum of 15 characters, stopping at the first whitespace

for(int i=0; names[i] != NULL; i++){ // Run through the names
    if(strcmp(buffer, names[i]) == 0){ // Are these two strings the same?
        printf("Day number %d \n", i+1); // Add one because you want to start with one, not zero
        return;
    }
}

printf("Sorry, that's not a valid day"); // We'll only get here if we didn't `return` earlier

我已将工作日名称存储为字符串，程序可以访问。但是比较字符串需要strcmp 函数而不是简单的==，所以我不能再使用switch-case，而必须使用循环。