【问题标题】:Spring MVC : Using User password to create a Java keystore, and access keys laterSpring MVC:使用用户密码创建 Java 密钥库,稍后访问密钥
【发布时间】:2015-05-02 22:46:06
【问题描述】:
  • 我正在开发一个 Spring-MVC 应用程序,其中有一个 Person 我使用 BCrypt 将密码存储在数据库中的类 格式。现在,我想使用 MD5 和创建一个 Java 密钥库 用户的明文密码。
    • 但由于我不知道 Spring-security 如何以及在何处获取明文密码并对其进行 BCrypt 以检查与数据库的对比,因此我无法使用明文密码来创建 MD5 和。
    • 我想在每次用户登录时重复此过程,以便我可以通过编程方式解锁密钥库并使用密钥名和 MD5 总和作为密码检索密钥。

我正在粘贴我的 Person 模型和 spring-security-application.xml :

 @Entity
@Table(name="person")
public class Person implements UserDetails{

    private static final GrantedAuthority USER_AUTH = new SimpleGrantedAuthority("ROLE_USER");

    private static final String emailRegexp = "^[a-zA-Z0-9_.+-]+@[a-zA-Z0-9-]+\\.[a-zA-Z0-9-.]+$";

    @Id
    @Column(name="id")
    @GeneratedValue(strategy = GenerationType.SEQUENCE,generator = "person_seq_gen")
    @SequenceGenerator(name = "person_seq_gen",sequenceName = "person_seq")
    private int id;

    @Valid
    @Email
    @Pattern(regexp = emailRegexp)
    @Column(name = "username")
    private String username;

    @Valid
    @NotEmpty(message = "Password may not be empty")
    @Column(name = "password")
    private String password;


 //getters and setters ommitted

}

PersonServiceImpl :

 @Override
    @Transactional
    public boolean addPerson(Person p) {
        try {
            Thread.sleep(2000);
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
        Person existingUser = personDAO.findPersonByUsername(p.getUsername());
        if(existingUser == null) {
            this.personDAO.addPerson(p);
            p.setAccountstatus(false);
            p.setOnetimeemail(false);
            p.setUsername(p.getUsername().toLowerCase());
            p.setPassword(BCrypt.hashpw(p.getPassword(), BCrypt.gensalt(11)));
            p.setUsername(p.getUsername().toLowerCase());
            this.personDAO.addPerson(p);
            sendAccountActivationEmail(p.getUsername(), p.getFirstName());
            return true;
        } else {
            return  false;
        }
    }

security-applicationContext.xml:

 <security:global-method-security pre-post-annotations="enabled" />

    <security:http create-session="ifRequired" use-expressions="true" auto-config="true" disable-url-rewriting="true">
        <security:form-login login-page="/login" default-target-url="/canvas/list" always-use-default-target="false" authentication-failure-url="/denied.jsp" />
        <security:remember-me key="_spring_security_remember_me" user-service-ref="userDetailsService" token-validity-seconds="1209600" data-source-ref="dataSource"/>
        <security:logout delete-cookies="JSESSIONID" invalidate-session="true" logout-url="/j_spring_security_logout"/>

<!--        <security:intercept-url pattern="/**" requires-channel="https"/> -->

  <!--  <security:port-mappings>
        <security:port-mapping http="80" https="443"/>
    </security:port-mappings>
-->
    </security:http>




    <!-- queries to be run on data -->
    <beans:bean id="rememberMeAuthenticationProvider" class="org.springframework.security.web.authentication.rememberme.PersistentTokenBasedRememberMeServices">
        <beans:property name="key" value="_spring_security_remember_me" />
        <beans:property name="tokenRepository" ref="jdbcTokenRepository"/>
        <beans:property name="userDetailsService" ref="LoginServiceImpl"/>
    </beans:bean>

    <!--Database management for remember-me -->
    <beans:bean id="jdbcTokenRepository"
                class="org.springframework.security.web.authentication.rememberme.JdbcTokenRepositoryImpl">
        <beans:property name="createTableOnStartup" value="false"/>
        <beans:property name="dataSource" ref="dataSource" />
    </beans:bean>

    <!-- Remember me ends here -->
    <security:authentication-manager alias="authenticationManager" erase-credentials="false">
        <security:authentication-provider user-service-ref="LoginServiceImpl">
           <security:password-encoder  ref="encoder"/>
        </security:authentication-provider>
    </security:authentication-manager>

    <beans:bean id="encoder"
                class="org.springframework.security.crypto.bcrypt.BCryptPasswordEncoder">
        <beans:constructor-arg name="strength" value="11" />
    </beans:bean>

    <beans:bean id="daoAuthenticationProvider"
                class="org.springframework.security.authentication.dao.DaoAuthenticationProvider">
                <beans:property name="userDetailsService" ref="LoginServiceImpl"/>
<security:global-method-security pre-post-annotations="enabled" />

<security:http create-session="ifRequired" use-expressions="true" auto-config="true" disable-url-rewriting="true">
    <security:form-login login-page="/login" default-target-url="/canvas/list" always-use-default-target="false" authentication-failure-url="/denied.jsp" />
    <security:remember-me key="_spring_security_remember_me" user-service-ref="userDetailsService" token-validity-seconds="1209600" data-source-ref="dataSource"/>
    <security:logout delete-cookies="JSESSIONID" invalidate-session="true" logout-url="/j_spring_security_logout"/>
</security:http>

<beans:bean id="rememberMeAuthenticationProvider" class="org.springframework.security.web.authentication.rememberme.PersistentTokenBasedRememberMeServices">
    <beans:property name="key" value="_spring_security_remember_me" />
    <beans:property name="tokenRepository" ref="jdbcTokenRepository"/>
    <beans:property name="userDetailsService" ref="LoginServiceImpl"/>
</beans:bean>
<beans:bean id="jdbcTokenRepository"
            class="org.springframework.security.web.authentication.rememberme.JdbcTokenRepositoryImpl">
    <beans:property name="createTableOnStartup" value="false"/>
    <beans:property name="dataSource" ref="dataSource" />
</beans:bean>
<security:authentication-manager alias="authenticationManager" erase-credentials="false">
    <security:authentication-provider user-service-ref="LoginServiceImpl">
       <security:password-encoder  ref="encoder"/>
    </security:authentication-provider>
</security:authentication-manager>

<beans:bean id="encoder"
            class="org.springframework.security.crypto.bcrypt.BCryptPasswordEncoder">
    <beans:constructor-arg name="strength" value="11" />
</beans:bean>

<beans:bean id="daoAuthenticationProvider"
            class="org.springframework.security.authentication.dao.DaoAuthenticationProvider">
            <beans:property name="userDetailsService" ref="LoginServiceImpl"/>
           <beans:property name="passwordEncoder" ref="encoder"/>
</beans:bean>
            <beans:property name="passwordEncoder" ref="encoder"/>
    </beans:bean>

登录服务实现:

@Transactional
@Service("userDetailsService")
public class LoginServiceImpl implements UserDetailsService{

    @Autowired private PersonDAO personDAO;
    @Autowired private Assembler assembler;


    @Override
    public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException,DataAccessException {
        Person person = personDAO.findPersonByUsername(username.toLowerCase());
            if(person == null) { throw new UsernameNotFoundException("Wrong username or password");} //Never specify which one was it exactly
        return assembler.buildUserFromUserEntity(person);
    }

    public LoginServiceImpl() {
    }
}

汇编器:

@Service("assembler")
public class Assembler {
    @Transactional(readOnly = true)
    User buildUserFromUserEntity(Person userEntity){
        String username = userEntity.getUsername().toLowerCase();
        String password = userEntity.getPassword();

        boolean enabled = userEntity.isEnabled();
        boolean accountNonExpired = userEntity.isAccountNonExpired();
        boolean credentialsNonExpired = userEntity.isCredentialsNonExpired();
        boolean accountNonLocked = userEntity.isAccountNonLocked();

        Collection<GrantedAuthority> authorities = new ArrayList<>();
        authorities.add(new SimpleGrantedAuthority("ROLE_USER"));

        return new User(username,password,enabled,accountNonExpired,credentialsNonExpired,accountNonLocked,authorities);
        }
}

我希望我说的很清楚,如果有任何疑问,请告诉我.. 任何帮助都会很好。非常感谢... :-)

【问题讨论】:

  • 查看UsernamePasswordAuthenticationFilter
  • @chrylis :谢谢,我没有实现 UsernamePasswordAuthenticationFilter。在这种情况下我该怎么办?我查了一下,我相信你的意思是使用 public static final String SPRING_SECURITY_FORM_PASSWORD_KEY。
  • 你没有实现它。我说看看;这就是您要询问的代码所在的位置。

标签: java spring-mvc encryption spring-security keystore


【解决方案1】:

您可以让 Spring Security 将密码保存在会话中:

<authentication-manager alias="authenticationManager" erase-credentials="false">
  <!-- authentication provider(s) -->
</authentication-manager>

然后您可以使用以下方法找回密码:

Authentication currentAuth = ...;
String pwd = currentAuth.getCredentials().toString();

要捕捉用户登录的时间,您可以listen for AuthenticationSuccessEvent

【讨论】:

  • 你好,我试过你的代码。我只是在另一种方法中使用它。我调用了Authentication authentication = SecurityContextHolder.getContext().getAuthentication();,然后是 authentication.getCredentials.toString。我只得到了用户名作为回报。你能告诉我我应该怎么做才能得到密码吗?
  • @WeareBorg getCredentials() 通常会返回密码,但可能因配置而异。您的安全配置中有什么奇怪的地方吗?
  • 不,我正在编辑我的帖子以粘贴完整的 security-application-context.xml。我还将粘贴用于 findByUsername 和构建实体的 Assembler 和 LoginServiceImpl。请给我5分钟。 :-)
  • 完成。请看一看。 :-)
  • 成功了,我什至不需要扩展 UsernamePasswordAuthenticationFilter。我只是将 false 设置为擦除凭据,并通过身份验证对象获取密码。非常感谢。 :-)