【发布时间】:2016-04-26 11:16:17
【问题描述】:
我现在正在处理以下问题一周。请耐心等待我解释。
我想要实现的是,对于我们中的一些人来说,这很简单,但是刚接触 WPF 会让事情变得困难。
上面的图像是通过将(已经有)svg 转换为xaml 然后将其导入到 Visual Studio 来呈现的。这就是 xaml 的样子。
<Canvas x:Name="Main" Margin="158,-223,-148,233">
<Canvas.RenderTransform>
<MatrixTransform Matrix="1.25 0 0 -1.25 -197.1231 961.58875"/>
</Canvas.RenderTransform>
<Path xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" Name="path139746" Fill="#FFD3BC5F" Canvas.Left="399.4" Canvas.Top="-172.6">
<Path.Data>
<PathGeometry Figures="m 66.611178 552.33853 c -4.36996 0.6305 -8.8334 0.97293 -13.3752 0.97293 -18.11465 0 -35.027 -5.21161 -49.34949 -14.18974 l 21.64732 -36.67733 c 8.2963 5.25686 18.12667 8.31294 28.67512 8.31294 2.7121 0 5.37755 -0.20365 7.98106 -0.59283 l 2.23539 -0.38916 c 4.72288 -0.91109 9.2226 -2.43913 13.41755 -4.49964 l 35.933612 77.65818 c -12.53504 5.94167 -26.095762 10.06571 -40.347392 12.0342 0 0 -2.27764 -21.55688 -4.54327 -42.98252 l -2.2747 0.35297 z" FillRule="nonzero"/>
</Path.Data>
</Path>
<Path xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" Fill="#FFD3BC5F" Canvas.Left="401" Canvas.Top="-173" >
<Path.Data>
<PathGeometry x:Name="path139750" Figures="m -21.311892 515.98804 c -11.7053 -15.57594 -18.6547 -34.92004 -18.6622 -55.85694 l 35.53987 0 5.06525 -0.024 c 0.63507 11.4535 4.86922 21.94 11.58023 30.3706 l 1.44647 1.7423 c 2.94008 3.3894 6.29329 6.4077 9.98888 8.9736 l -43.53754 73.76488 c -13.18956 -8.30539 -24.88746 -18.76176 -34.60186 -30.87743 0 0 17.3968 -13.23944 34.61076 -26.3386 l -1.42986 -1.75428 z" FillRule="nonzero"/>
</Path.Data>
</Path>
<Path xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" Name="path139780" Fill="#FFD3BC5F" Canvas.Left="401.4" Canvas.Top="-167.6">
<Path.Data>
<PathGeometry Figures="m 214.75854 460.1016 94.92962 0 0 69.86866 -94.92962 0 0 -69.86866 z" FillRule="nonzero"/>
</Path.Data>
</Path>
<Path xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" Name="path139784" Fill="#FFD3BC5F" Canvas.Left="401.4" Canvas.Top="-167.6">
<Path.Data>
<PathGeometry Figures="m 211.64803 529.825 -36.87191 0 -62.32503 -69.72236 100.95576 0 0 69.74499 -1.75882 -0.0226 z" FillRule="nonzero"/>
</Path.Data>
</Path>
<Path xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" Fill="#FFD3BC5F" Canvas.Top="-173" Canvas.Left="401">
<Path.Data>
<PathGeometry x:Name="path139798" Figures="m -41.482092 460.131 -43.5377 0 c 0.6744 30.93022 11.4414 59.36853 29.1278 82.17137 l 33.3799 -25.40184 c -11.9001 -15.82789 -18.9641 -35.4887 -18.97 -56.76953" FillRule="nonzero"/>
</Path.Data>
</Path>
<Path xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" Name="path139802" Fill="#FFD3BC5F" Canvas.Left="399.4" Canvas.Top="-172.6">
<Path.Data>
<PathGeometry Figures="m 139.82292 494.54117 c -13.01467 -14.5593 -25.97803 -29.06131 -30.40076 -34.00892 0 0 -2.72123 28.49563 -29.566602 43.70507 l 17.54746 37.92328 c 19.158502 -10.35383 34.278952 -27.22704 42.419902 -47.61943" FillRule="nonzero"/>
</Path.Data>
</Path>
<Path xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" Name="path139806" Fill="#FFD3BC5F" Canvas.Left="399.4" Canvas.Top="-172.6">
<Path.Data>
<PathGeometry Figures="m 98.037008 543.53024 17.776782 38.41802 c 23.1211 -11.42479 42.62202 -29.06882 56.29587 -50.76297 l 0.18403 -0.31676 c 0 0 -15.53072 -17.37553 -31.34655 -35.06934 -8.34762 20.43762 -23.62341 37.33197 -42.910132 47.73105" FillRule="nonzero"/>
</Path.Data>
</Path>
<Path xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" Name="path139810" Fill="#FFD3BC5F" Canvas.Left="399.4" Canvas.Top="-172.6">
<Path.Data>
<PathGeometry Figures="m 53.235488 554.82033 c -18.39362 0 -35.56859 -5.28853 -50.11595 -14.3994 l -21.08756 35.73002 c 21.04842 12.78086 45.75185 20.14348 72.17809 20.14348 5.74697 0 11.40815 -0.36201 16.97265 -1.03931 l -4.37747 -41.4213 c -4.43321 0.63805 -8.96144 0.98651 -13.56976 0.98651" FillRule="nonzero"/>
</Path.Data>
</Path>
<Rectangle Name="object_to_move" Fill="LightBlue" Height="36" Stroke="Black" Width="41" Canvas.Left="330" Canvas.Top="229"/>
我想要的是沿路径动画/移动框(矩形),使其(框)看起来像旅行,并使用它(路径)作为继续前进的道路。
我尝试过使用DoubleAnimationUsingPath。但是我很困惑,我认为我没有正确使用东西。
我找到了以下代码片段并尝试对其进行操作并将其应用到我的示例中,但无法使其正常工作。
// path139798.Freeze(); // For performance benefits.
DoubleAnimationUsingPath daPath = new DoubleAnimationUsingPath();
daPath.Duration = TimeSpan.FromSeconds(5);
daPath.RepeatBehavior = RepeatBehavior.Forever;
daPath.AccelerationRatio = 0.6;
daPath.DecelerationRatio = 0.4;
daPath.AutoReverse = true;
daPath.PathGeometry = path139798;
daPath.Source = PathAnimationSource.X;
circle2.BeginAnimation(Canvas.LeftProperty, daPath);
daPath = new DoubleAnimationUsingPath();
daPath.Duration = TimeSpan.FromSeconds(5);
daPath.RepeatBehavior = RepeatBehavior.Forever;
daPath.AccelerationRatio = 0.6;
daPath.DecelerationRatio = 0.4;
daPath.AutoReverse = true;
daPath.PathGeometry = path139798;
daPath.Source = PathAnimationSource.Y;
circle2.BeginAnimation(Canvas.TopProperty, daPath);
}
有人可以帮忙吗?谢谢!
【问题讨论】:
-
哦,这看起来很有趣。所以我看到的所有定义都是path139798。这是否意味着您只是想让它遵循具有该名称的左下角第一个形状的路径?看起来您的其他形状几乎像迷宫一样开始,所以我想我会问,因为根据您的解释,我无法想象您想要的结果。
-
@ChrisW。嘿,感谢您抽出时间询问。我试图让框遵循我上面描述的形状,只有在代码示例中只是一个形状(你是对的),但是,代码示例不起作用。我只是想通过仅使用 1 个路径名来检查我是否做对了我没有做的事情来找出出路。再说一遍,我只是想让盒子沿着形状移动。
-
好吧,你需要一个一致的路径来定义你的运动路径,注意将你的图片加载到油漆或其他东西中,然后画一条矩形应该作为路径的粗线?
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@ChrisW。如果我只是把它画在那里,我可以从油漆中导入它吗?
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哦,不,大声笑,我的意思只是一个快速的模型,向我们展示预期的路径,这样我就可以举出一个例子。