【发布时间】:2009-11-26 01:14:12
【问题描述】:
我只想进行一些直接的转换(几乎只是搜索和替换),但我无法将东西放在适当的位置 - 我最终发现链接不合适并且内容重复。我确定我在尝试遍历 xml 时做了一些愚蠢的事情:)
我正在尝试:
builder = Nokogiri::HTML::Builder.new do |doc|
doc.html {
doc.body {
doc.div.wrapper! {
doc.h1 "Short"
xm.css('paragraph').each do |para|
doc.h3.para(:id => para['number']) { doc.text para['number'] }
doc.p.narrativeparagraph {
xm.css('paragraph inner-section').each do |section|
doc.span.innersection { doc.text section.content
xm.css('inner-section xref').each do |xref|
doc.a(:href => "#" + xref['number']) { doc.text xref['number'] }
end
xm.css('paragraph inner-text').each do |innertext|
doc.span.innertext { doc.text innertext.content }
end
} end #inner-section
}
end#end paragraph
}#end wrapper
}#end body
}#end html
end#end builder
开:
<?xml version="1.0"?>
<looseleaf>
<paragraph number="1">
<inner-section> blah one blah <xref number="link1location"></xref>
<inner-text> blah two blah blah </inner-text>
blah three
</inner-section>
</paragraph>
<paragraph number="2">
<inner-section> blah four blah <xref number="link2location"></xref>
<inner-text>blah five blah blah </inner-text>
blah six
</inner-section>
</paragraph>
</looseleaf>
创建:
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" "http://www.w3.org/TR/REC- html40/loose.dtd">
<html>
<body>
<div id="wrapper">
<h1>Short</h1>
<h3 class="para" id="1">1</h3>
<p class="narrativeparagraph">
<span class="innersection"> blah one blah <a href="#link1location">link1location</a>
<span class="innertext"> blah two blah blah </span>
blah three</span>
</p>
<h3 class="para" id="2">2</h3>
<p class="narrativeparagraph">
<span class="innersection"> blah four blah <a ref="#link2location">link2location</a>
<span class="innertext">blah five blah blah </span>
blah six</span></p>
我一直在尝试各种方法以使其正常工作,基本的 html 结构还可以,但段落的子级是一团糟 - 任何帮助将不胜感激。 问候, 里奇
【问题讨论】:
-
任何和我在同一条船上的菜鸟 - 我已经放弃尝试使用 Builder,我正在缓慢但肯定地到达那里: frag.xpath("//paragraph").each { |div| div.name = "p"; div.set_attribute("class" , "narrativeparagraph") } frag.css('inner-section xref').each { |xref|外部参照名称=“一个”; xref.set_attribute("href" , "#" + xref['number']);外部参照内容 = 外部参照['编号'] }
-
您作为示例给出的 html - 是您喜欢 构建的吗?你能提供一个实际结果的例子吗?
标签: html xml transform nokogiri